Finding Constants in Limit Expressions

Finding Constants in Limit Expressions

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to find the constants a and b such that the limit as x approaches 1 of (x^2 + ax + b)/(x - 1) equals 5. The instructor highlights that both the numerator and denominator must approach zero for the limit to be a constant. By setting the numerator to zero, a relationship between a and b is established. The instructor then substitutes values to solve for a and b, concluding with a equals 3 and b equals -4.

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8 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main goal of the problem introduced in the video?

To solve for x in a quadratic equation.

To find the derivative of a function.

To find the value of x that makes the expression zero.

To determine the constants a and b such that a limit equals 5.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why must the numerator also approach zero as x approaches 1?

Because the numerator is always zero.

Because x is approaching infinity.

Because the limit is a constant.

Because the denominator approaches zero.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation is set up to find the relationship between a and b?

x^2 + ax + b = 0

1 + a + b = 0

x^2 + ax + b = 5

a + b = 5

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the expression for b substituted into the original limit equation?

By replacing b with a constant value.

By setting b equal to zero.

By expressing b in terms of a.

By using the quadratic formula.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of factoring the numerator in the limit expression?

To change the variable of the expression.

To eliminate the denominator.

To find the roots of the equation.

To simplify the expression for easier calculation.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens after canceling terms in the limit expression?

The expression is simplified to find a.

The limit is set to zero.

The limit becomes undefined.

The expression becomes a quadratic equation.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Once a is found, how is b determined?

By using the quadratic formula.

By setting b equal to zero.

By solving a new equation for b.

By substituting a back into the equation for b.

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the final values of a and b?

a = 2, b = -3

a = 3, b = -4

a = 1, b = -2

a = 0, b = 5