Collinearity and Vector Relationships

Collinearity and Vector Relationships

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to determine if three points are collinear by using vectors. It introduces the concept of collinear points and vectors, defines the points P, Q, and R, and explains the condition for collinearity. The tutorial then demonstrates how to calculate the vectors PQ and QR, and find the scalar multiple K that proves collinearity. The video concludes with a verification of the collinearity and discusses alternative methods to show collinearity.

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does it mean for vectors to be collinear?

They lie on the same line.

They are parallel to each other.

They are perpendicular to each other.

They have the same magnitude.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following points are given in the problem?

P(-2, 3), Q(6, 5), R(2, -6)

P(2, -3), Q(6, -5), R(-6, 2)

P(3, 2), Q(5, -6), R(2, 6)

P(2, 3), Q(-6, 5), R(6, 2)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the condition for points to be collinear?

PQ should have the same magnitude as QR

PQ should be perpendicular to QR

PQ should be a scalar multiple of QR

PQ should be equal to QR

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is vector PQ calculated?

By subtracting coordinates of R from Q

By adding coordinates of P and Q

By subtracting coordinates of P from Q

By adding coordinates of Q and R

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for vector QR?

-6 - 6, -2 - 5

6 + 6, 2 + 5

6 - 6, 2 - 5

6 - 2, 5 - 6

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derived value of K for the x-component?

-8/12

8/12

-12/8

12/8

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the value of K simplified?

By multiplying both numerator and denominator by 4

By dividing both numerator and denominator by 4

By dividing both numerator and denominator by 2

By multiplying both numerator and denominator by 2

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