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Lateral and Total Surface Area of Cylinders

Lateral and Total Surface Area of Cylinders

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Practice Problem

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to determine a missing dimension of a cylinder when given its total surface area. It covers calculating the base area and perimeter, finding the missing height using algebra, and solving for the total surface area. Additionally, it demonstrates how to calculate the lateral surface area, excluding the bases, using the perimeter and height.

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21 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving for a missing dimension when given the total surface area of a cylinder?

Determine the weight of the cylinder.

Identify the missing dimension.

Calculate the volume of the cylinder.

Find the diameter of the base.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which formula is used to calculate the area of the face of a cylinder?

2πrh

2πr

πr²

πd

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for the perimeter of the base of a cylinder?

2πrh

πd

2πr

πr²

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the formula 2πr in the context of a cylinder?

It calculates the height.

It calculates the area of the base.

It calculates the perimeter of the base.

It calculates the volume.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the given problem, what is the radius of the cylinder?

3.5 meters

2.5 meters

4.0 meters

1.5 meters

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the area of the base of a cylinder?

Multiply the diameter by π.

Multiply the radius by the height.

Add the radius and height.

Square the radius and multiply by π.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of the radius in calculating the area of the base?

It is divided by the height.

It is multiplied by the diameter.

It is added to the height.

It is squared and multiplied by π.

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