Circle Equations and Properties

Circle Equations and Properties

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

This video tutorial covers coordinate geometry, focusing on the equation of a circle. It explains how to derive the equation when the center and radius are given, and also when the center and a point on the circumference are known. The video includes examples to illustrate finding the equation of a circle and determining the center and radius from a given equation.

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8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of this video tutorial?

Finding the area of a circle

Understanding the properties of triangles

Learning about circle equations in coordinate geometry

Exploring the concept of parallel lines

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation of a circle when the center and radius are given?

(x + a)^2 + (y + b)^2 = r^2

x^2 + y^2 + 2gx + 2fy + c = 0

x^2 + y^2 = r^2

(x - a)^2 + (y - b)^2 = r^2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the equation of a circle simplified when the center is at the origin?

x^2 + y^2 + 2gx + 2fy + c = 0

x^2 + y^2 = r^2

(x + a)^2 + (y + b)^2 = r^2

(x - a)^2 + (y - b)^2 = r^2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the general form of a circle's equation?

x^2 + y^2 = r^2

(x - a)^2 + (y - b)^2 = r^2

x^2 + y^2 + 2gx + 2fy + c = 0

(x + a)^2 + (y + b)^2 = r^2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you find the center of a circle from its general equation?

By identifying the coefficients of x and y

By using the formula (-g, -f)

By calculating the midpoint of the diameter

By finding the intersection of tangents

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example problem, what is the equation of the circle with center (4, 5) and radius 3?

(x - 4)^2 + (y - 5)^2 = 9

x^2 + y^2 = 9

(x + 4)^2 + (y + 5)^2 = 9

x^2 + y^2 + 2gx + 2fy + c = 0

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you find the center and radius from the equation 4x^2 + 4y^2 - 12x - 8y + 9 = 0?

By finding the midpoint of the diameter

By using the distance formula

By dividing through by 4 and comparing coefficients

By completing the square

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation of a circle if the center is (1, 5) and it passes through (-4, 1)?

(x - 1)^2 + (y - 5)^2 = 25

(x + 1)^2 + (y + 5)^2 = 25

x^2 + y^2 - 2x - 10y - 15 = 0

x^2 + y^2 + 2x + 10y + 15 = 0