Understanding Gradient and Differentiation

Understanding Gradient and Differentiation

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video introduces the concept of the gradient of a straight line, explaining it as the rate at which something changes. Using an example of a linear relationship between the area of a property and its cost, the video demonstrates how to calculate the gradient by dividing the difference in cost by the difference in area. It further explains the link between the gradient and the rate of change, using the operator dy/dx for generalization to XY axes. An example with the equation y=3x+2 is provided to illustrate the concept. The video concludes with an introduction to differentiation, highlighting its significance in advanced mathematics.

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15 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary concept introduced in the video?

The volume of a cube

The perimeter of a rectangle

The area of a circle

The gradient of a straight line

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example given, what is the relationship between area and cost?

Quadratic

Linear

Exponential

Logarithmic

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How much do you pay for every 10 square meters in the example?

100 pounds

90 pounds

50 pounds

70 pounds

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the gradient of the line represent in the example?

The initial cost

The rate of cost change with area

The change in area

The total cost

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the gradient of the line in the example?

5

7

9

11

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does 'dc by da' represent in the context of the video?

The change in cost with respect to area

The change in area with respect to cost

The total cost

The total area

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the general form of the gradient in terms of x and y?

y by x

x by y

dy by dx

dx by dy

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