Optimization Problems in Geometry

Optimization Problems in Geometry

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

In this video, Mark Barceman discusses optimization problems involving two variables. The video covers two examples: maximizing the area of a rectangular corral and minimizing the cost of a chicken yard fence. Both examples involve setting up equations and using calculus to find solutions. The video concludes with a comparison of the examples and their relevance to real-world business situations.

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11 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of the video presented by Mark Barceman?

Basics of algebra

Introduction to calculus

Geometry concepts

Discussion on optimization

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of optimization problems are introduced in this video?

Non-linear optimization problems

Linear programming problems

Single variable problems

Two variable applied max-min problems

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which section of the textbook is the material in this video similar to?

Section 6.3

Section 4.6

Section 3.2

Section 5.1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are some complications mentioned in optimization problems?

They are always linear

They may involve more than one variable

They are always easy to solve

They have no real-world applications

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first example, what is the farmer trying to achieve with the fence?

Build a circular fence

Minimize the cost

Enclose the largest possible area

Use the least amount of material

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation representing the total length of the fence in the first example?

2x + y = 900

x^2 + y^2 = 900

x + 2y = 900

x + y = 900

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the dimensions of the fence that maximize the area in the first example?

x = 150, y = 600

x = 225, y = 450

x = 300, y = 300

x = 200, y = 500

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