Tangent Secant Theorem Concepts

Tangent Secant Theorem Concepts

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains the tangent secant theorem, which states that the product of the lengths of a secant segment and its external segment is equal to the square of the length of the tangent segment. The video provides a detailed proof using angle-angle similarity of triangles and the alternate segment theorem. The tutorial concludes with a summary of the theorem and its proof.

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of the Tangent Secant Theorem?

The relationship between two secants.

The relationship between a chord and a tangent.

The relationship between a secant and a tangent.

The relationship between two tangents.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

According to the Tangent Secant Theorem, what is the product of the lengths PA and PB equal to?

The square of PA.

The difference between PT and PA.

The sum of PT and PB.

The square of PT.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the diagram, which line represents the tangent?

The yellow line.

The green line.

The red line.

The blue line.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in proving the Tangent Secant Theorem?

Identifying the center of the circle.

Calculating the length of the tangent.

Drawing a perpendicular from the center.

Joining specific points to form triangles.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which theorem is used to establish the angle relationships in the proof?

Sine Rule.

Pythagorean Theorem.

Alternate Segment Theorem.

Angle Bisector Theorem.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the common angle in triangles PBT and PTA?

Angle at point A.

Angle at point B.

Angle at point P.

Angle at point T.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How are the triangles PBT and PTA proven to be similar?

By having equal areas.

By having equal sides.

By having equal angles.

By having equal perimeters.

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