Children's Age and Equation Problems

The video tutorial explains how to solve a problem involving a neighborhood recreation program with 280 children aged 11 or 12. The sum of their ages is 3230 years. The tutorial guides viewers through setting up equations to represent the problem, isolating variables, and substituting values to solve for the number of 11-year-olds. The solution involves calculating the total student years and using basic algebra to find the answer.

How many children are served by the neighborhood recreation program?

• 320

• 250

• 300

• 280

What is the total sum of the children's ages in the program?

• 2800 years

• 3500 years

• 3000 years

• 3230 years

What are the two age groups of children in the program?

• 10 and 12 years

• 12 and 13 years

• 11 and 12 years

• 10 and 11 years

What variable is used to represent the number of 11-year-olds?

• x

• y

• t

• e

What equation represents the total number of children?

• e / t = 280

• e + t = 280

• e - t = 280

• e * t = 280

What is the equation for the total sum of ages?

• 11e + 12t = 3230

• 11e - 12t = 3230

• 11e / 12t = 3230

• 11e * 12t = 3230

What is the first step in solving the equations?

• Add e to both sides

• Divide both sides by e

• Subtract e from both sides

• Multiply both sides by e

What expression represents the number of 12-year-olds?

• 280 - e

• 280 / e

• 280 + e

• 280 * e

What is the next step after isolating t?

• Add t to the age equation

• Multiply t by the age equation

• Substitute t into the age equation

• Divide t by the age equation

What is the result of 12 times 280?

• 2800

• 3360

• 3230

• 3500