Proportional Relationships and Unit Rates

This video tutorial covers Math 7 Unit 4 Lesson 3, focusing on revisiting proportional relationships. It explains the concept of constant proportionality and how to use it to solve various mathematical problems. The lesson includes practical applications, such as calculating costs and mixing ratios, and provides strategies for writing equations and setting up proportions. The tutorial concludes with homework problems and practice exercises to reinforce the concepts learned.

What is the constant proportionality (K value) used for in proportional relationships?

• To solve problems involving proportional relationships

• To calculate the average of two quantities

• To find the difference between two quantities

• To determine the sum of two quantities

In the recipe ratio problem, what is the K value when using half a cup of sugar and one cup of flour?

• 1

• 2

• 0.5

• 1.5

How much does one foot of rope cost if 6 feet cost $7.50?

• $1.25

• $1.50

• $1.00

• $2.00

What is the unit rate in the rope cost problem?

• $1.50 per foot

• $1.00 per foot

• $1.25 per foot

• $2.00 per foot

How can you solve proportional problems using tables?

• By dividing the largest value

• By subtracting the smallest value

• By finding the constant proportionality

• By adding all values

What is the K value for Tyler's swimming speed problem?

• 2/1

• 4/5

• 5/4

• 1/2

How many bottles of sparkling water are produced for every 8 bottles of plain water?

• 3

• 6

• 5

• 8

In the paint mixing problem, what is the K value when mixing blue and white paint?

• 2/3

• 3/2

• 5/2

• 10/3

What equation represents the proportional relationship in the first scenario?

• y = 3/2 x

• y = 2/3 x

• y = 5/4 x

• y = 4/5 x

How long does it take for a nerve signal to travel 5.5 feet at 250 feet per second?

• 1.00 seconds

• 0.75 seconds

• 0.55 seconds

• 0.22 seconds