
Dynamic Programming in Matrix Multiplication
Interactive Video
•
Computers
•
9th - 10th Grade
•
Practice Problem
•
Hard
Thomas White
FREE Resource
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8 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the main focus of the matrix chain multiplication problem?
Solving linear equations
Calculating the determinant of matrices
Determining the optimal order of multiplication
Finding the product of matrices
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which condition must be met for two matrices to be multiplied?
Both matrices must have the same dimensions
Both matrices must be square matrices
The number of columns in the first matrix must equal the number of rows in the second matrix
The number of rows in the first matrix must equal the number of columns in the second matrix
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the cost of multiplying two matrices determined?
By the sum of the elements in both matrices
By the number of scalar multiplications required
By multiplying the number of rows and columns of both matrices
By adding the dimensions of the matrices
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the goal of the matrix chain multiplication problem?
To find the largest matrix in the chain
To calculate the inverse of each matrix
To determine the order of multiplication that minimizes the total cost
To find the product of all matrices
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does dynamic programming help achieve in matrix chain multiplication?
It reduces the number of matrices
It simplifies the matrices
It provides a method to try all possibilities and find the optimal solution
It helps find the inverse of matrices
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in filling the dynamic programming table?
Calculate the determinant of each matrix
Fill the diagonal with zeros
Multiply all matrices together
Find the inverse of each matrix
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the formula used in dynamic programming for matrix chain multiplication?
M[i, j] = M[i-1, j] * M[i, j+1]
M[i, j] = min(M[i, k] + M[k+1, j] + d[i-1]*d[k]*d[j])
M[i, j] = M[i, j-1] + M[i+1, j]
M[i, j] = M[i, j] + M[i+1, j+1]
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