Integration and Substitution Techniques

Integration and Substitution Techniques

Assessment

Interactive Video

Mathematics

11th - 12th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains the process of performing definite integrals, focusing on the importance of changing the limits of integration when substituting variables. It highlights common mistakes, such as not adjusting limits for definite integrals, and provides a step-by-step guide on using the substitution method. The tutorial also demonstrates how to replace variables and apply new limits effectively.

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a definite integral?

An integral with variable limits

An integral that cannot be solved

An integral without limits

An integral with specified limits

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving a definite integral with substitution?

Change the variable

Solve the integral directly

Ignore the limits

Use a calculator

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to change the limits of integration when substituting variables?

To ensure the integral remains indefinite

To avoid solving the integral

To maintain the accuracy of the integral

To simplify the integral

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of changing variables in an integral?

To avoid solving the integral

To change the integral type

To simplify the integral

To make the integral more complex

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the differential dx when du is 7x?

dx becomes 1/7 du

dx becomes 7 du

dx remains unchanged

dx becomes 17th du

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What should you not forget when changing variables in a definite integral?

The original limits

The new limits

The original variable

The original function

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for dx in terms of du when du is 7x?

dx = 7 du

dx = 1/7 du

dx = 17th du

dx = 1/17 du

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