Understanding Exponential Functions

Understanding Exponential Functions

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains transformations in exponential functions, focusing on the roles of 'a', 'b', and 'h'. It discusses how 'b' affects graph growth, 'a' impacts the y-intercept, and 'h' causes horizontal shifts. The tutorial also covers graphing the function and understanding asymptotes, providing a comprehensive overview of exponential function transformations.

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7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the effect of increasing the value of 'b' in an exponential function?

The graph decreases more slowly.

The graph reflects over the x-axis.

The graph increases more quickly.

The graph remains unchanged.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the 'a' value affect the graph of an exponential function?

It shifts the graph horizontally.

It reflects the graph over the y-axis.

It vertically stretches or compresses the graph.

It changes the asymptote.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the graph when 'h' is negative?

The graph moves up.

The graph moves down.

The graph shifts to the right.

The graph shifts to the left.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the equation is y = 2 * b^(x + 2), what is the value of 'h'?

-2

0

2

1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to graph with one point in exponential functions?

To find the y-intercept.

To understand the graph's direction.

To determine the slope.

To identify the asymptote.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What characterizes a typical growth function when 'b' is greater than one?

The graph decreases.

The graph remains constant.

The graph reflects over the y-axis.

The graph increases.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Where is the asymptote located if the graph is not moved up or down?

At y = 1

At x = 0

At x = 1

At y = 0