Geometry Concepts and Formulas

Geometry Concepts and Formulas

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial covers the properties and formulas of quadrilaterals, including squares, rectangles, rhombuses, and parallelograms. It demonstrates problem-solving using these formulas, with a focus on applying Pythagorean triples in quadrilateral problems. The tutorial also explores breaking down complex quadrilaterals into triangles to find areas, emphasizing the importance of understanding geometric properties and relationships.

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9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for the area of a square with side length s?

s + s

2s

s^2

4s

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the perimeter of a rectangle?

base + height

4 * base

base * height

2(base + height)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the tile and border problem, what is the total number of gray tiles when n equals 24?

144

48

24

576

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the ratio of the area covered by gray tiles to the total area of the large square?

100%

64%

50%

75%

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for the area of a rhombus with diagonals D1 and D2?

D1 * D2

D1 + D2

D1^2 + D2^2

1/2 * D1 * D2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the area of a parallelogram calculated?

Base^2 + Height^2

Base * Height

1/2 * Base * Height

Base + Height

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a trapezoid, how is the area determined?

Average of bases * height

Base * height

1/2 * base * height

Base + height

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a key observation when dealing with Pythagorean triples in quadrilaterals?

They always form a square

They indicate a right triangle

They are irrelevant

They form a circle

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the complex problem-solving section, what is the significance of finding common heights in triangles?

It simplifies area calculations

It complicates the problem

It is unnecessary

It only applies to circles