Solving Quadratic Equations Concepts

Solving Quadratic Equations Concepts

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to solve a quadratic equation using the quadratic formula. It begins by setting the equation to zero and identifying the coefficients a, b, and c. The instructor then demonstrates how to plug these values into the quadratic formula and simplify the expression. The process involves calculating the discriminant and finding the square root to determine the roots of the equation. Finally, the video shows how to interpret the plus or minus sign in the formula to find the two possible solutions, which are x = 5 and x = -7.

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving a quadratic equation using the quadratic formula?

Add a constant to both sides

Identify the roots

Multiply both sides by a constant

Set the equation to zero

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What operation is performed to both sides of the equation to set it to zero?

Subtract 105

Divide by 6

Add 105

Multiply by 3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the coefficients a, b, and c in the equation 3x^2 + 6x - 105 = 0?

a = 6, b = 3, c = 105

a = 1, b = 2, c = 3

a = 3, b = 6, c = -105

a = 3, b = -6, c = 105

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of identifying the coefficients a, b, and c?

To simplify the equation

To graph the equation

To substitute them into the quadratic formula

To find the vertex of the parabola

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the quadratic formula used to find the roots of a quadratic equation?

x = (-b ± √(b^2 - 4ac)) / 2a

x = (b ± √(b^2 + 4ac)) / 2a

x = (b ± √(b^2 - 4ac)) / a

x = (-b ± √(b^2 + 4ac)) / a

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of b^2 - 4ac for the equation 3x^2 + 6x - 105 = 0?

105

1260

36

1296

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of multiplying 12 by 105 in the context of this problem?

1150

1050

1200

1260

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