Circle Equations and Functions

Circle Equations and Functions

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explores whether the equation of a circle defines a function. It begins by solving the circle's equation for y, revealing that it does not define a function due to multiple outputs for a single input. The video then analyzes the graph of a circle, showing that a vertical line intersects it twice, confirming it is not a function. However, the circle contains graphs of two functions: the upper semicircle and the lower semicircle. The tutorial defines these functions and examines their domains and ranges, concluding that each semicircle is a function as they intersect vertical lines at only one point.

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main topic discussed in the video?

Understanding trigonometric identities

Graphing linear functions

Solving quadratic equations

Determining if a circle equation defines a function

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation of the circle discussed in the video?

x^2 + y^2 = 1

x^2 - y^2 = 1

x^2 + y = 1

x + y^2 = 1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why does the equation x^2 + y^2 = 1 not define a function?

It is not continuous

It has multiple y-values for a single x-value

It does not pass through the origin

It is not a polynomial equation

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the vertical line test indicate about a graph?

If it is a parabola

If it is a function

If it is a line

If it is a circle

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function for the upper semicircle?

f(x) = x^2 - 1

f(x) = 1 - x^2

f(x) = √(1 - x^2)

f(x) = -√(1 - x^2)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the domain of the function for the upper semicircle?

[-1, 1]

[0, 1]

[1, 2]

[-1, 0]

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function for the lower semicircle?

g(x) = 1 - x^2

g(x) = x^2 - 1

g(x) = √(1 - x^2)

g(x) = -√(1 - x^2)

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