Fermat's Little Theorem Concepts

Fermat's Little Theorem Concepts

Assessment

Interactive Video

Created by

Thomas White

Mathematics

11th - 12th Grade

Hard

The video tutorial explains Fermat's Little Theorem, which states that if P is a prime number and the GCD of a and P is 1, then a^(P-1) is congruent to 1 mod P. The proof involves considering a set of numbers and showing they are incongruent modulo P. By relating the product of these numbers to a factorial, the proof concludes using Wilson's theorem, demonstrating the theorem's validity.

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19 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main condition for Fermat's Little Theorem to hold?

P must be a composite number.

The GCD of a and P must be greater than 1.

a must be a prime number.

P must be a prime number.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In Fermat's Little Theorem, what is the result of a^(P-1) mod P?

0

a

P

1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of considering the set S in the proof?

To find the sum of elements.

To demonstrate congruence of elements.

To calculate the factorial of P.

To show incongruence of elements modulo P.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the set S consist of in the proof?

a, 2a, 3a, ..., (P-1)a, Pa

0, 1, 2, ..., P-1

1, 2, 3, ..., P

a, a^2, a^3, ..., a^(P-1)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't P divide a in the proof?

Because a is a prime number.

Because the GCD of a and P is 1.

Because a is greater than P.

Because P is a composite number.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the set S' in the proof?

It is used to find the product of elements.

It represents the residues modulo P.

It is used to calculate the sum of elements.

It is used to demonstrate congruence.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the proof show about the elements of set S?

They are all equal to a.

They are all incongruent modulo P.

They are all congruent modulo P.

They are all equal to P.

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