What is the primary condition for a graph to have an Euler circuit?

Euler Circuits and Graph Properties

Interactive Video
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Mathematics
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9th - 10th Grade
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Hard

Thomas White
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19 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
All vertices must have even degrees.
The graph must be a tree.
The graph must be directed.
All vertices must have odd degrees.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the first graph, why was it initially determined that there was no Euler circuit?
The graph was directed.
The graph had too many edges.
There were vertices with odd degrees.
The graph was disconnected.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What was the solution to create an Euler circuit in the first graph?
Reuse existing edges to make all degrees even.
Convert the graph to a tree.
Remove some edges.
Add new vertices.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the second graph, what was the challenge in connecting the odd degree vertices?
They were part of a cycle.
They were already even.
They were isolated vertices.
They were not directly connected by an edge.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How was the issue of odd degree vertices resolved in the second graph?
By adding new edges.
By removing some vertices.
By reusing edges to connect through other vertices.
By converting the graph to a directed graph.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What was the final step to ensure all vertices had even degrees in the second graph?
Adding a new vertex.
Reusing four edges.
Removing an edge.
Converting the graph to a tree.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the third graph, what was the initial observation about the degrees of the vertices?
All vertices had even degrees.
The graph was disconnected.
Some vertices had odd degrees.
All vertices had odd degrees.
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