Function Inverses and Composition

Function Inverses and Composition

Assessment

Interactive Video

Mathematics

11th - 12th Grade

Hard

Created by

Thomas White

FREE Resource

This video introduces the concept of inverse trigonometric functions, focusing on their relationship with functions. It explains that an inverse function exists only if the original function is bijective, meaning it is both one-to-one and onto. The video also discusses the conditions necessary for the existence of inverse functions and explores the relationship between the composition of functions and inverse functions. The video concludes with a summary and a preview of the next video, which will delve deeper into inverse trigonometric functions.

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13 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of the new chapter introduced in the video?

Probability

Calculus

Linear equations

Inverse trigonometric functions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which branch of mathematics is briefly mentioned in the introduction?

Geometry

Trigonometry

Statistics

Algebra

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Under what condition does a function have an inverse?

If it is a constant function

If it is a quadratic function

If it is a linear function

If it is a bijective function

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does it mean for a function to be bijective?

It is neither one-to-one nor onto

It is only onto

It is only one-to-one

It is both one-to-one and onto

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the inverse of a function f from set A to set B?

A function from B to A

A function from A to C

A function from A to A

A function from B to B

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the notation used for the inverse of a function f?

f prime

f double prime

f inverse

f star

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between G and F if G is the inverse of F?

G is from C to B

G is from A to C

G is from A to B

G is from B to A

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