Mole Lab Pre-Lab

Mole Lab Pre-Lab

Assessment

Interactive Video

Hard

Created by

Patrick Dougherty

FREE Resource

4 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of COPPER?

58.7 g/mol

58.9 g/mol

63.5 g/mol

29 g/mol

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the conversion factor used to convert FROM moles of H2O TO molecules of H2O? Pay attention to what goes in the numerator and denominator in the conversion factor.  

\frac{1 mole H_{2}O}{18.0 grams H_{2}O}

 

\frac{18 molecules H_{2}O}{1 mole H_{2}O}

 

\frac{18.0 grams H_{2}O}{1 mole H_{2}O}

 

\frac{1 mole H_{2}O}{6.02 x 10^{23}molecules H_{2}O}

\frac{6.02x10^{23}molecules H_{2}O}{1 mole H_{2}O}

 

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If you used 0.350 grams of chalk in 3 signatures, how much chalk was used in 1 signature (assuming the signatures are completely identical)?

1.05 g

0.117 g

neither of the options are correct.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which conversion factor would you use to covert FROM the grams of calcium carbonate used TO moles of calcium carbonate,assuming chalk is 100% calcium carbonate? (Pay attention to what goes in the numerator and denominator in the conversion factor)

\frac{1 mole \cdot calcium carbonate}{grams\cdot from \cdot the \cdot periodic \cdot table}

\frac{1 mole\cdot calcium carbonate}{6.02x10^{23}grams\cdot calcium carbonate}

 

\frac{grams\cdot from\cdot the\cdot periodic\cdot table}{1 mole\cdot calcium carbonate}

\frac{6.02x10^{23}grams\cdot calciumcarbonate}{1 mole\cdot calcium carbonate}