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WorksheetsTurunan kelas XI
Total questions: 29
Worksheet time: 3570secs
Name
Class
Date
1.
Determine in which interval this function
f(x) = x4 - 6x3+2x + 8 is concave downward?
f(x) = x4 - 6x3+2x + 8 is concave downward?
a)
0<x<3
b)
x>3
c)
x<0
d)
no solution
2.
Identify the interval on the derivative graph where it is decreasing and concave up
a)
-1<x-1
b)
-3<x<-1
c)
-2<x-1
d)
1<x<3
3.
Identify the interval on the derivative graph where it is decreasing and concave down
a)
1<x<3
b)
3<x<4
c)
2<x<3
d)
-3<x<-1
4.
Identify the interval where it is decreasing and concave up
a)
1<x<3
b)
0<x<1
c)
6<x<8
d)
5<x<6
5.
Identify the interval on the derivative graph where it is decreasing and concave down
a)
1<x<3
b)
3<x<4
c)
4<x<5
d)
6<x<8
6.
Identify the interval where the derivative graph is decreasing and concave down
a)
3<x<4
b)
1<x<3
c)
1<x<2
d)
0<x<1
7.
Identify the interval on the derivative graph where it is increasing and concave down
a)
-2.5<x<-2
b)
2<x<2.5
c)
0<x<2
d)
-1<x<0
8.
Identify the interval where the derivative graph is decreasing and concave down.
a)
1<x<2
b)
-1<x<0
c)
-2<x<-1
d)
0<x<1
9.
Identify the interval where the derivative graph is decreasing and concave up.
a)
1<x<2
b)
2<x<3
c)
1<x<3
d)
3<x<4
10.
Determine in which interval this function
f(x) = x4 - 6x3+2x + 8 is concave upward ?
f(x) = x4 - 6x3+2x + 8 is concave upward ?
a)
0<x<3
b)
x>3
c)
x<0
d)
x<0 and x>3
11.
Determine the absolute maximum value and absolute minimum respectively in the interval [0,10]
a)
AMaxV=f(10)=14,
AMinV = f(0) = 0
AMinV = f(0) = 0
b)
AMaxV = f(9) = 9,
AMinV = f(0) = 0
AMinV = f(0) = 0
c)
AMaxV = f(3) = 9,
AMinV = f(7) = 5
AMinV = f(7) = 5
d)
AMaxV = f(7) = 5,
AMinV = f(3) = 9
AMinV = f(3) = 9
12.
Determine the absolute maximum value and absolute minimum respectively in the interval [1,9]
a)
AMaxV=f(10)=14,
AMinV = f(0) = 0
AMinV = f(0) = 0
b)
AMaxV=f(3)=f(9)=9,
AMinV = f(0) = 0
AMinV = f(0) = 0
c)
AMaxV = f(3)=f(9)=9,
AMinV = f(1)=f(7) = 5
AMinV = f(1)=f(7) = 5
d)
AMaxV = f(7) = 5,
AMinV = f(3) = 9
AMinV = f(3) = 9
13.
Determine the absolute maximum value and absolute minimum respectively in the interval [2,5]
a)
AMaxV=f(10)=14,
AMinV = f(0) = 0
AMinV = f(0) = 0
b)
AMaxV=f(3)=9,
AMinV = f(5)=7
AMinV = f(5)=7
c)
AMaxV = f(3)=f(9)=9,
AMinV = f(1)=f(7) = 5
AMinV = f(1)=f(7) = 5
d)
AMaxV = f(7) = 5,
AMinV = f(3) = 9
AMinV = f(3) = 9
14.
Find the absolute Maximum value for this following function
a)
No Maximum
b)
x = 0 and x = 6
c)
f ''(0) = 0
d)
f "(6) = 144
15.
Find the absolute Maximum value and the minimum value respectively for this following function:
f(x) = 8x3- 2x4
f(x) = 8x3- 2x4
a)
AMaxV= f(3) = 54
AMinV = f(0) = 0
AMinV = f(0) = 0
b)
AMaxV= f(3) = 54
No Minimum
No Minimum
c)
No Max
AMinV = f(0) = 0
AMinV = f(0) = 0
d)
No Max and No Min
16.
Find the critical points of f(x) = 2x4- 4x2 + 1
a)
x= 0
b)
x = -1, 1
c)
x = -1, 0, 1
d)
no critical points
17.
What are the intervals of the graph increasing for f(x) = 2x4- 4x2 + 1
a)
(-1,0)
b)
(0,1)
c)
(-∞,-1) and (1,∞)
d)
(-1,0) υ(1, ∞)
18.
If given f'(x) how would you find the intervals which the graph f(x) has a positive slope?
a)
f'(x) < 0 (negative)
b)
f'(x) > 0 (positive)
c)
f'(x) is increasing
d)
Can't be determined
19.
Find the derivative of f(x) = 6x30 -2x15 + 4x3 - 2x + 1
a)
f'(x) = 18x29 + 30x15 + 12x3
b)
f'(x) = 180x29 - 30x14 + 12x2
c)
f'(x) = 180x29 - 30x14 + 12x2 - 2
d)
f'(x) = 180x29 - 30x14 + 12x2 +1
20.
Find s'(t) if s(t) = -t2 - t, given that v(t)=s'(t).
a)
v(t) = -2
b)
v(t) -2t - 1
c)
v(t) = t3
d)
v(t) = -t
21.
Find the derivative: h(x)=(3x+2)(5x3+2x)
a)
(3x+2)(15x2+2x)+(5x3+2x)(3)
b)
(3x+2)(15x2+2)(5x3+2x)(3)
c)
(3x+2)(15x2+2)+(5x3+2x)(3)
d)
60x3+30x2+12x+4
22.
An absolute maximum must occur at a critical point or at an endpoint.
a)
True
b)
False
23.
A critical number, c, or a function f is a number in the domain of f such that:
a)
f'(c) = 0
b)
f'(c) is undefined
c)
f'(c) = o or f'(c) is undefined
d)
None of the above
24.
If c is a critical number then f(c) is either a local maximum or a local minimum
a)
True
b)
False
25.
Find the critical points of f(x) = 2x4- 4x2 + 1
a)
x= 0
b)
x = -1, 1
c)
x = -1, 0, 1
d)
no critical points
26.
Find the point(s) of inflection for f(x) = 2(x)1/5 + 3
a)
None
b)
x = 0
c)
x = 0, 2
d)
x = -2, 0, 2
27.
If given f'(x) how do you find the values of x at which f(x) has a point of inflection?
a)
f"(critical point)
b)
f'(x) DNE
c)
f'(x) = 0
d)
The max or min of f'(x)
28.
If given f'(x) how would you find if f(x) is concave down?
a)
f'(x) = 0
b)
f'(x) (increasing) or f"(x) > 0
c)
f'(x) <(decreasing) of f"(x) < 0
d)
Can't be determined
29.
If given f'(x) how would you find the intervals which the graph f(x) has a positive slope?
a)
f'(x) < 0 (negative)
b)
f'(x) > 0 (positive)
c)
f'(x) is increasing
d)
Can't be determined
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