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Solving Systems by Substitution

Total questions: 11

Worksheet time: 55mins

Name
Class
Date
1.
What is the first step in solving a system by Substitution?
a)
Make sure both equations are in standard form.
b)
Make sure at least one equation is solved for one variable.
c)
Make sure both equations are in slope-intercept form.
d)
Make sure both equations can be solved.
2.
Solve this system of equations. 
y = 2x + 1
y = 4x - 1
a)
(1,3)
b)
(-1,-3)
c)
(-1,3)
d)
(3,1)
3.
y = -2x + 5
y = 2x - 11
a)
No Solution
b)
(0, 0)
c)
(3, -1)
d)
(4, -3)
4.
Solve the system by substitution.
 

5x + 4y= −14
y =  −7x  −  15 
a)
(-2, -1)
b)
(1, -2)
c)
(-2, 1)
d)
(-1, -2)
5.
Solve:
y = 2x -11
-3y = -6x -15
a)
(-1.5,-4)
b)
(1.5,4)
c)
No solution (parallel lines)
d)
Infinitely many solutions
6.
x + 2y = 2
x = -4y + 2
a)
(-3, 0)
b)
(0, 2)
c)
(-3, -2)
d)
(2, 0)
7.
x - 3y = -13
4x + 2y = 4
a)
(1, 4)
b)
(-1, -4)
c)
(-1, 4)
d)
(1, -4)
8.
y = -6x + 5
-2x + y = 5
a)
(-3, -6)
b)
(-6, 3)
c)
(0, 5)
d)
(-3, 5)
9.
y = -3x + 11
y = -6x - 13
a)
(-8, 35)
b)
(8, -13)
c)
(1, 8)
d)
(2, 13)
10.
y = -2x + 5
y = 2x - 11
a)
No Solution
b)
(0, 0)
c)
(3, -1)
d)
(4, -3)
11.
Solve for x and y
y = 2x + 1
y = 4x - 1
a)
(1,3)
b)
(-1,-3)
c)
(-1,3)
d)
(3,1)