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WorksheetsIED 3rd Quarter Review
Total questions: 59
Worksheet time: 36mins
Џ Φ 0.50 ↓0.25
Џ Φ 0.50 ↓0.25
Џ Φ 0.250 ↓0.5
V Φ 0.250 ↓0.5
V0.75 x 810
V0.75 x 810
V0.25 x 810
V0.75 x 180
A horizontal 12 foot long beam is attached to a vertical wall. A force is applied to the beam as shown. What is the magnitude and direction of the moment applied by the applied force? M=F*d
-360 ft*lb (CW)
+360 ft*lb (CCW)
360 ft*lb
360 (CW)
A horizontal 3 foot long beam is attached to a vertical wall at point P. A force is applied to the beam as shown. What is the magnitude and direction of the moment applied by the applied force? M=F*d
+37.5 ft*lb (CCW)
-37.5 ft*lb (CW)
-45 ft*lb (CW)
45 ft*lb (CCW)
A 4 ft x 4 ft x 4 ft box weighs 150 pounds, and the weight is evenly distributed. What is the magnitude and direction of the moment of the weight of the box?
300 lb
150 lb
600 lb
100 lb
A 2 ft x 2 ft x 2 ft box weighs 100 pounds, and the weight is evenly distributed. What is the magnitude of the minimum horizontal force, T, required at the top edge of the box to tip the box over? Assume the box will not slide when the force is applied. f*d=f*d
100 lb
50 lb
200 lb
25 lb
A horizontal 3 foot long beam is attached to a vertical wall at point P. The beam is a "W18x40" beam, which is 18" high, and weighs 40 lbs per foot. How much force needs to be applied at point A in order to support the weight of the beam and maintain static equilibrium? f*d=f*d
72 lbs CCW
72 lbs CW
180 lbs CW
120 lbs CCW
5, 15, 10, 20, 15, 10, 15
60, 58, 52, 48, 60, 67
{70, 70, 80, 85, 85, 90, 95, 95, 100, 100}
