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dihybrid pea plants

Total questions: 33

Worksheet time: 17mins

Name
Class
Date
1.

parents genotype

a)

TTYy-TTYY

b)

Ttyy-ttYy

c)

Ttyy-TTYy

d)

ttYY-ttYY

2.

TTYy first letter from FOIL method (first from each group)

a)

Ty

b)

TY

3.

TTYy o from foil (outter group)

a)

TY

b)

Ty

4.

TTYy i from foil (inner group)

a)

TY

b)

Ty

5.

TTYy l from foil (last group)

a)

TY

b)

Ty

6.

answer for box 1

a)

ttYy

b)

TTYY

c)

TtYy

d)

TTYy

7.

what is the answer for box 2

a)

ttyy

b)

Ttyy

c)

TtYy

8.

how many out of 16 will have the genotype TTYy

a)

2-16

b)

3-16

c)

4-16

d)

8-16

9.

How many traits are crossed when using a dihybrid cross

a)

1

b)

2

c)

3

d)

4

10.

recessive albino x heterozygous for the albino trait--ALBINISM IS A RECESSIVE CONDITION aa

a)

F

b)

G

c)

H

d)

J

11.

HOW MANY TRAITS ARE BEING CROSSED IN THIS PICTURE

a)

ONE=MONOHYBRID CROSS

b)

TWO=DIHYBRID CROSS

c)

THREE=TRIHYBRID CROSS

d)

FOUR=QUADHYBRID CROSS

12.

MEIOSIS PRODUCES

a)

DIPLOID(DOUBLE) SEX CELLS

b)

HAPLOID(HALF) SEX CELLS

13.

MITOSIS PRODUCES

a)

DIPLOID-DOUBLE- BODY CELLS

b)

HAPLOID-HALF- BODY CELLS

c)

DIPLOID-DOUBLE- SEX CELLS

d)

HAPLOID-HALF- SEX CELLS

14.

___________________IS AN ALTERNATE FORM FOR A GENE THAT CODES FOR A TRAIT.

a)

GEBOTYPE

b)

PHENOTYPE

c)

ALLELE

d)

SEX LINKED TRAIT

15.

PARENTS ARE

a)

HOMOZYGOUS-AA AND HETEROZYGOUS-Aa

b)

HOMOZYGOUS-aa AND HOMOZYGOUS-AA

c)

HETEROZYGOUS Hh AND HETEROZYGOUS Hh

16.

box one

a)

ll

b)

Ll

c)

LL

17.

Box 4

a)

ll

b)

Ll

c)

LL

18.

two heterozygous hairy stem plants have what genotype

a)

HHxHH

b)

Hhxhh

c)

HhxHh

d)

hhxhh

19.

T=hairy stem

t=normal stem

Whats the resulting phenotypic results?

a)

50% hairy-50% normal

b)

75% hairy-25% normal

c)

25% hairy-75% normal

d)

BB-25%, Bb-50%, bb-25%

20.

how many out of 16 will be YyRr

a)

2-16

b)

3-16

c)

4-16

d)

1-16

21.

How many out of 16 will be yyrr

a)

1-16

b)

2-16

c)

3-16

d)

4-16

22.

BbFf parent-What goes in box 1

a)

BF

b)

Bf

c)

bF

d)

bf

23.

BbFf What goes in box 2

a)

BF

b)

Bf

c)

bf

d)

bF

24.

How many are heterozygous for both traits?

a)

9 out of 16

b)

4 out of 16

c)

3 out of 16

d)

1 out of 16

25.

Albino=aa recessive condition - normal is dominant AA,Aa.

cross a normal male thats heterozygous with an albino female. give the resulting genotype

a)

a

b)

b

c)

c

d)

d

26.

How how many will have TTYy out of 16?

a)

9-16

b)

4-16

c)

3-16

d)

1-16

27.

sex linked recessive problem

Normal vision female with a colorblind father have a child with a normal vision male. whats the genotype of the parents?

a)

XCXC and XCY

b)

XCXc and XcY

c)

XcXc and XCY

d)

XCXc and XCY

28.

sex linked recessive problem

Normal vision female with a colorblind father have a child with a normal vision male. whats the chance of a colorblind son?

a)

25%

b)

50%

c)

75%

d)

0%

29.

sex linked recessive problem

Normal vision female with a colorblind father have a child with a normal vision male. whats the chance of a colorblind daughter?

a)

0%

b)

25%

c)

50%

d)

75%

30.

cross two normal feather birds, what is the chance of getting frizzy feathers?

a)

75%

b)

50%

c)

25%

d)

0%

31.

Blood Type cross

Homozygous A crossed with Homozygous B

What blood type could result

a)

A and B

b)

AB

c)

O

d)

A,B,AB, and O

32.

BB BO IBIB IBi= blood type for

a)

A

b)

B

c)

AB

d)

O

33.

BO IS THE SAME blood type AS

a)

IBIB

b)

ii

c)

IBi

d)

IB