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WorksheetsDihybrids
Total questions: 14
Worksheet time: 1hrs 4mins
What is the genotype for a pea plant homozygous for round seeds (R), and heterozygous for yellow seeds (Y)?
RrYy
RRyy
RRYy
rryy
A parent with genotype YyRR could produce which gametes?
YR, YR, yR, yR
Yy, Rr, yy, rr
Yr, Yr, yr, yR
YR, YR, yr, yr
A parent with genotype SsYy could produce what gametes?
SY, Sy, sY, sy
SY, SY, sy, sy
Sy, Sy, Sy, Sy
Sy, Sy, sY, sY
What genotype would go in box 1?
AABb
AABB
aabb
AaBb
What genotype would go in box 3?
AABb
Aabb
aabb
AaBB
What genotype would go in box 13?
AaBb
aabb
AABB
AAbb
If you cross two homozygous plants (RRYY x rryy)
R = round seeds, r = wrinkled seeds Y = yellow seeds, y = green seeds
What percent will have round and yellow seeds?
0%
25%
50%
100%
In peas, round is dominant to wrinkled and yellow is dominant to green. Based on this dihybrid cross, what fraction of the offspring will have wrinkled, yellow seeds?
9/16
3/16
1/16
16/16
A white mouse with red eyes is crossed with a black mouse with brown eyes. The white mouse is recessive for both of its traits. The black mouse is dominant for both of its traits.
This cross would be
BBEE x bbee
BBEe x BbEe
BbEE x BbEe
BBee x BBEE
A male beetle has the genotype Ttbb. If this beetle mates with a female with genotype TTBb, what is the chance their offspring will have the genotype TtBb?
12.5% (2/16)
25% (4/16)
50% (8/16)
75% (12/16)
In cocker spaniels, black coat color (B) is dominant over red (b), and solid color (S) is dominant over spotted (s). If a red male was crossed with a black female to produce a red spotted puppy, the genotypes of the parents (with male genotype first) would be
Bb Ss x Bb Ss.
bb Ss x Bb Ss.
bb ss x Bb Ss.
bb Ss x Bb ss.
Bb ss x Bb ss.
