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Dihybrids

Total questions: 14

Worksheet time: 1hrs 4mins

Name
Class
Date
1.
In a dihybrid cross
a)
one trait is crossed.
b)
two traits are crossed.
c)
four boxes are needed for the punnett square.
d)
mom's alleles are dominant.
2.

What is the genotype for a pea plant homozygous for round seeds (R), and heterozygous for yellow seeds (Y)?

a)

RrYy

b)

RRyy

c)

RRYy

d)

rryy

3.
What gamete possibilities could come from this parent's genotype?
a)
AB, AB, aB, aB
b)
Ab, AB, Ab, ab
c)
Ab, Ab, Ab, Ab
d)
AB, aB, ab, aB
4.

A parent with genotype YyRR could produce which gametes?

a)

YR, YR, yR, yR

b)

Yy, Rr, yy, rr

c)

Yr, Yr, yr, yR

d)

YR, YR, yr, yr

5.

A parent with genotype SsYy could produce what gametes?

a)

SY, Sy, sY, sy

b)

SY, SY, sy, sy

c)

Sy, Sy, Sy, Sy

d)

Sy, Sy, sY, sY

6.

What genotype would go in box 1?

a)

AABb

b)

AABB

c)

aabb

d)

AaBb

7.

What genotype would go in box 3?

a)

AABb

b)

Aabb

c)

aabb

d)

AaBB

8.

What genotype would go in box 13?

a)

AaBb

b)

aabb

c)

AABB

d)

AAbb

9.

If you cross two homozygous plants (RRYY x rryy)

R = round seeds, r = wrinkled seeds Y = yellow seeds, y = green seeds

What percent will have round and yellow seeds?

a)

0%

b)

25%

c)

50%

d)

100%

10.

In peas, round is dominant to wrinkled and yellow is dominant to green. Based on this dihybrid cross, what fraction of the offspring will have wrinkled, yellow seeds?

a)

9/16

b)

3/16

c)

1/16

d)

16/16

11.

A white mouse with red eyes is crossed with a black mouse with brown eyes. The white mouse is recessive for both of its traits. The black mouse is dominant for both of its traits.

This cross would be

a)

BBEE x bbee

b)

BBEe x BbEe

c)

BbEE x BbEe

d)

BBee x BBEE

12.
What fraction of offspring from the cross AaBB x Aabb will be heterozygous for both traits?
a)
1/16
b)
4/16
c)
8/16
d)
3/16
13.

A male beetle has the genotype Ttbb. If this beetle mates with a female with genotype TTBb, what is the chance their offspring will have the genotype TtBb?

a)

12.5% (2/16)

b)

25% (4/16)

c)

50% (8/16)

d)

75% (12/16)

14.

In cocker spaniels, black coat color (B) is dominant over red (b), and solid color (S) is dominant over spotted (s). If a red male was crossed with a black female to produce a red spotted puppy, the genotypes of the parents (with male genotype first) would be

a)

Bb Ss x Bb Ss.

b)

bb Ss x Bb Ss.

c)

bb ss x Bb Ss.

d)

bb Ss x Bb ss.

e)

Bb ss x Bb ss.