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Total questions: 25
Worksheet time: 19mins
-12∫ (6x2-4x+7) dx = ...
33
22
11
9
∫24 (2x+7)3 dx = ...
(2x+7)4+c
24(2x+7)4+c
6(2x+7)4+c
3(2x+7)4+c
∫60x (x2+7)4 dx = ...
60x (x2+7)5+c
12 (x2+7)5+c
6 (x2+7)5+c
6x (x2+7)5+c
∫6x √x2+1 dx = ...
6x (x2+1)√x2+1 +c
2 (x2+1)√x2+1 +c
4x (x2+1)√x2+1 +c
6 (x2+1)√x2+1 +c
∫x5 dx = ...
72x3 x+ C
52x3x + C
5x4 + C
61x6 + C
5x4 + C
∫(54x3− 4x2+x24−7)dx = ...
51x4−34x3−4x−1−7x + c
51x4−34x3+4x−1−7x+c
51x4−34x3−4x−1−7+c
51x4−8x3−34x2−7x+c
512x4−8x3−4x−1−7x+c
∫ (1−2x2)6x dx = ...
−20(1−2x2)51+c
20(1−2x2)51+c
−5(1−2x2)51+c
5(1−2x2)51+c
∫xx2−1 dx = ...
3x(x2−1)23+c
31(x2−1)32+c
31(x2−1)23+c
3x(x2−1)32+c
∫3x(x2+5)3 dx = ...
31(x2+5)x2+5+c
3(x2+5)25+c
51(x2+5)25+c
53(x2+5)2x2+5+c
∫14(x21−x)dx = ...
1867
−1247
−1124
2140
Jika f′(x)= 3x2−6x+2 dan f(1)=4, maka f(x) adalah ...
x3−3x2+3x+4
x3−3x2+2x+4
x3−3x2+x+4
x3−3x2+2x−4
x3−3x2+3x−7
∫4x3−3x2+6x+2 dx=
4x4−x3+3x2+2x+c
x4−x3+3x2+2x+c
4x4−x3+6x2+2x+c
x4−3x3+3x2+2x+c
x4−x3+6x2+2x+c
∫234x3−6x2−2x+5 dx=
33
-33
27
-27
39
Hasil ∫ 8x3+12x2−6x+5 dx jika diketahui f(1)=2 adalah ...
f(x)=2x4+4x3−3x2+5x−4
f(x)=2x4+4x3−3x2+5x−6
f(x)=2x4+4x3−3x2+5x+6
f(x)=2x4+4x3−3x2+5x+4
f(x)=2x4+4x3−3x2+5x−5
∫2x1+3x2dx=...
921+3x2+C
92(1+3x2)3+C
92((1+3x2)32)+C
92((1+3x2)31)+C
92((1+3x2)41)+C
Jika f′(x)=1−2x dan f(3)=4 maka nilai f(x)=...
2x2−x−11
x2+2x+11
−2x2+x+10
−x2+2x+10
−x2+x+10
∫02(2x−1)(x2−x−2)4dx=....
−532
−516
58
516
532
∫12x2(x3−2)7dx = ....
( gunakan aturan integral subtitusi )
21(x3+2)8+C
41(x3−2)7+C
31(x3−2)8+C
21(x3−2)8+C
21(x3−2)9+C
∫(2x−1)2x2−2x+5 dx=...
41(2x2−2x+5)(2x2−2x+5)3+C
31(2x2−2x+5)2x2−2x+5+C
41(2x2−2x+5)2x2−2x+5+C
312x2−2x+5+C
31(2x2−2x+5)22x2−2x+5+C
∫(4x+3)(4x2+6x−9)9dx=...
101(4x2+6x−9)10+C
151(4x2+6x−9)10+C
201(4x2+6x−9)10+C
301(4x2+6x−9)10+C
351(4x2+6x−9)10+C
Jika f′(x)= 3x2−6x+2 dan f(1)=4, maka f(x) adalah ...
x3−3x2+3x+4
x3−3x2+2x+4
x3−3x2+x+4
x3−3x2+2x−4
x3−3x2+3x−7
∫1a(2x−1)dx = 6 . Nilai a = ...
4
3
2
1
0
∫4(3x+ 5)5dx=....
98(3x+5)6+C
96(3x+5)6+C
94(3x+5)6+C
92(3x+5)6+C
91(3x+5)6+C
∫6x(x+2)5dx=....
72(3x+1)(x+2)6+C
71(3x+1)(x+2)6+C
72(3x−1)(x+2)6+C
71(3x−1)(x+2)6+C
−71(3x+1)(x+2)6+C
∫x2x−4dx=....
152(3x2−2x−8)2x−4+C
154(3x2−2x−8)x−2+C
152(3x2+2x−8)2x−4+C
154(3x2+2x−8)x−2+C
154(3x2−2x+8)x−2+C
