WorksheetsUnit V Review - RADT 1075
Total questions: 40
Worksheet time: 20mins
If the intensity of radiation at 36 inches is 480 mGy, what is the intensity if the SID is increased to 72 inches?
360 mGy
240 mGy
120 mGy
60 mGy
Whenever magnification is increased:
spatial resolution is decreased
spatial resolution is increased
spatial resolution stays the same
exposure to the image receptor increases
The formula to determine the SOD (source to object distance) is:
SOD = SID – OID
SOD = OID – SID
SOD = SID + OID
none of these
With digital imaging, it is impossible to overexpose the patient to radiation because the computer makes adjustments to the image.
True
False
The distance between the x-ray focal spot and the image receptor is the:
OID
SID
MF
SOD
The inverse square law describes the relationship between __ and __.
kVp and exposure
mAs and exposure
distance and beam intensity
kVp and beam intensity
The controlling factor for exposure when using a digital image receptor is:
SID
mAs
OID
IR type
Higher kVp results in less absorption and more variation in the intensities of photons exiting the patient.
True
False
Increasing the kVp by 15% has the same effect on exposure as
increasing the mAs by 15%.
doubling the mAs.
decreasing the mAs by 15%.
halving the mAs.
Which of the following is the correct formula for the inverse square law?
I1/I2 = D1/D2.
I1/I2 = D2/D1.
I1/I2 = (D1)2/(D2)2.
I1/I2 = (D2)2/(D1)2.
With digital imaging, the relationship between mAs and image brightness is
direct
direct proportional
inverse
none of these
Changes in SID affect
exposure
spatial resolution
contrast
distortion
The distance between the object being imaged and the image receptor is the:
OID
SID
MF
SOD
Focal spot size affects only:
exposure
contrast
sharpness
noise
The relationship between kVp and the quantity of remnant radiation is known as the:
kVp-exposure rule
15% rule
115% rule
kVp-quantity rule
When OID cannot be reduced, it is possible to reduce size distortion by:
increasing mAs
increasing SID
using a small focal spot size
decreasing SID
What is the size of the object when the MF is 1.3 and the image size is 3 cm?
0.43 cm
1.3 cm
2.3 cm
3.9 cm
Imaging a thicker body part will result in an image with
less IR density
less IR exposure
the same IR exposure
more IR exposure
What type of relationship does mAs have with SID when the goal is to keep the exposure to the IR constant?
direct proportional
direct but not proportional
inverse proportional
inverse but not proportional
With digital imaging, if the image receptor is not exposed to enough radiation:
the image brightness will appear low (dark)
the image brightness will appear appropriate
the image brightness will appear high (light)
the image will show quantum mottle
When a patient cannot fully extend his or her leg for a knee image, resulting in the knee being 4 inches away from the image receptor, what is the MF if the SID is 40 inches?
0.1
0.9
1.11
10
What type of relationship do mAs have with the quantity of x-rays produced?
direct proportional
direct but not proportional
inverse proportional
inverse but not proportional
To maintain the same amount of radiation reaching the IR, if the kVp is increased by 15% the mAs needs to:
remain the same
be doubled
be halved
be decreased by a minimum of 30%
Tube angulation may result in elongation and reduced exposure to the IR.
True
False
The indication of how much magnification is seen on a radiograph is:
OID
SID
MF
SOD
__ SID and __ OID results in increased magnification.
increased; increased
decreased; decreased
increased, decreased
decreased; increased
A magnification factor of 1 cannot be achieved with radiographic imaging.
True
False
If the magnification factor is 1.25, the image is __ than the object.
25% smaller
125% smaller
25% larger
125% larger
Increasing the kVp:
increases the energy of the x-ray photons
increases the quantity of x-ray photons
increases the penetrating power of x-ray photons
all of these
Shape distortion is due to misalignment of the tube and/or part.
True
False
The distance between the x-ray focal spot and the object being imaged is the
OID
SID
MF
SOD
Which of the following is the formula to determine magnification factor?
MF = SID/OID.
MF = SID/SOD.
MF = SOD/SID.
MF = OID/SID.
Using a higher SID
increases magnification
decreases magnification
increases size distortion
none of these
Quantum noise is a result of
too few x-ray photons reaching the image receptor
too many x-ray photons reaching the image receptor
x-rays with energy that is too high reaching the image receptor
Which of the following matrices results in a digital image with the best image quality?
200 × 200
600 × 600
1024 × 1024
2048 × 2048
Distortion is misrepresentation of the size or shape of the anatomy being imaged.
True
False
Visibility of the anatomic structures is accomplished by balancing
brightness
exposure
contrast
The ability of the imaging system to distinguish between two structures is
latitude
resolution
contrast
distortion
In order to preserve the true shape of the part in the image, what three factors should be properly aligned?
X-ray tube/central ray
lmage receptor
Object to Image Distance
Anatomic part
It is impossible to produce a radiographic image without unsharpness.
true
false
