WorksheetsQuiz 4: Topic 4 - Genetic Inheritance
Total questions: 20
Worksheet time: 15mins
A plant with purple flowers is allowed to self-pollinate. Generation after generation, it
produces purple flowers. This is an example of …
hybridization.
true-breeding
incomplete dominance
the law of segregation.
In Mendel’s time, most people believed that …
all genetic traits bred true.
the characteristics of parents were blended in the offspring.
acquired characteristics were inherited.
the inheritance of traits was controlled by blood.
If short hair (L) is dominant to long hair (l), animals LL and Ll have the same …
genotypes.
phenotypes.
alleles.
genes.
What is a genetic cross called between an individual of unknown genotype and a homozygous recessive?
A self-cross
A test cross
An F1 cross
A dihybrid cross
How many sex chromosomes are found in a human male liver cell?
1
2
23
46
Which of the following terms is least related to the others?
Homozygous
Tetrad
Recessive
Heterozygous
If all offspring of a cross have the genotype Aa, the parents of the cross would most likely be…
AA x aa
Aa x aa
Aa x Aa.
AA x Aa
The usual F2 phenotypic ratio of a monohybrid cross is …
1:1.
2:1.
9:3:3:1.
3:1
P = purple, p = white. The offspring of a cross of two heterozygous purple-flowering plants results in …
all purple-flowered plants.
purple-flowered plants and white-flowered plants.
two types of white-flowered plants: PP and Pp.
all white-flowered plants.
Assume short hair (L) is dominant to long hair (l) and black hair (B) is dominant to brown (b). If you found a black short-haired animal, you could determine its genotype by crossing it to an animal with a genotype of …
LLBB.
llbb.
llBB.
LLbb
The usual F2 phenotypic ratio of a dihybrid cross is …
1:1.
2:1.
9:3:3:1.
1:2:1.
Some dogs have erect ears; others have drooping ears. Some dogs bark when following a scent; others are silent. Erect ears and barking are due to dominant alleles located on different chromosomes. A dog homozygous for both dominant traits is mated to a droopy-eared, silent follower. The phenotypic ratio expected in the F1 generation is …
9:3:3:1.
100 percent of one phenotype.
1:1.
1:2:1.
A genetic cross of inbred snapdragons with red flowers with inbred snapdragons with white flowers resulted in F1 hybrid offspring that all had pink flowers. When the F1 plants were self- pollinated, the resulting F2 generation plants had a phenotypic ratio of 1 red: 2 pink: 1 white. The most likely explanation is:
pink flowers are the result of a blending of the red and white genotypes.
flower colour is due to 2 or more complementary genes.
heterozygous plants have a different phenotype than either inbred parent because of incomplete dominance of the dominant allele.
flower color inheritance in snapdragons does not behave as a Mendelian trait.
A woman with type A blood and a man with type B blood could potentially have offspring with which of the following blood types?
Type A
Type B
Type AB
All of the above
A person does not have antigen A or antigen B in the red blood cells. What is his blood type?
Blood type O
Blood type AB
Blood type A
Blood type B
A couple has four children, and each child has a different blood type. What is the blood type of the parents?
Type A and type B
Type B and type AB
Type AB and type O
Type A and type O
A man who carries an X-linked allele will pass it on to …
all of his daughters.
half of his daughters.
all of his sons.
all of his children.
Which of the following is the evidence used mainly in the construction of a linkage map?
Rf value
Crossover value
RQ value
Microscopy
Genes W, X, Y and Z are linked on the same chromosome. The following are the cross-over values between the genes.
W and X – 38%
W and Y – 26%
X and Z – 16%
Y and Z – 4%
The sequence of genes on the chromosome is …
W Y Z X
W Z Y X .
Y Z X W
X Z Y W .
Given that alleles A and B are dominant, while alleles a and b are recessive. If the number of progenies for each phenotype from a test cross is 450, 450, 10 and 10 respectively, calculate the map distance between allele A and B.
1 cM
3 cM
6 cM
10 cM
