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Tentukan Nilai dari limx→0 1−cos 2xxtan2x\lim_{x\rightarrow0}\ \frac{1-\cos\ 2x}{x\tan2x}x→0lim xtan2x1−cos 2x adalah . . .
-2
-1
0
1
2
limx→0 sin 13xx\lim_{x\rightarrow0}\ \frac{\sin\ \frac{1}{3}x}{x}x→0lim xsin 31x
-3
−13-\frac{1}{3}−31
000
13\frac{1}{3}31
3
limx→0 7 sin x cos x2x\lim_{x\rightarrow0}\ \frac{7\ \sin\ x\ \cos\ x}{2x}x→0lim 2x7 sin x cos x
−72x-\frac{7}{2}x−27x
− 3,5-\ 3,5− 3,5
72\frac{7}{2}27
7
6
12
4
-1/6
1/3
1/6
2/9
-1/3
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