Free Printable Mixture Problems (Algebra)

1.

How many ounces of a 30% acid solution should be mixed with 40 ounces of a 2% acid solution to make a 5% acid solution?

a)

1.2 ounces

b)

12 ounces

c)

2 ounces

d)

4.8 ounces

2.

A 40 lb. bag of gravel that was 80% small stones by weight was mixed with another bag that was 60% small stones by weight to produce a new mixture that was 67% small stones by weight.

What was the weight of the other bag? Round to the nearest tenth of a lb.

a)

62.8 lbs.

b)

81.6 lbs.

c)

52.9 lbs.

d)

74.3 lbs.

3.

A chemist has 60 g of solution that is 70% acid. how much water should be added to make a solution that is 40% acid?

a)

40 g water

b)

50 g water

c)

45 g water

d)

15 g water

4.

How many kilograms of pure alcohol must be added to 40 kg of a 70% alcohol solution to produce an 85% alcohol solution?

a)

30 kg alcohol

b)

40 kg alcohol

c)

50 kg alcohol

d)

35 kg alcohol

5.

Which equation could help you find how many ounces of 30% acid solution should be mixed with 50 ounces of 2% acid solution to make 3% acid solution?

a)

$\frac{0.02\cdot50+0.30x}{50+x}=\frac{3}{100}$

b)

$\frac{0.30x}{50+x}=\frac{3}{100}$

c)

$\frac{0.30x}{50+0.02x}=\frac{3}{100}$

d)

$\frac{0.02\cdot50+0.30x}{50+3}=\frac{30}{100}$

6.

A chemist has 80 g of solution that is 65% acid. Which equation below could help you find how much water should be added to make a solution that is 45% acid?

a)

$\frac{0.65\cdot80}{80+x}=\frac{45}{100}$

b)

$\frac{0.65\cdot80+x}{80}=\frac{45}{100}$

c)

$\frac{0.65\cdot80+x}{80+x}=\frac{45}{100}$

d)

$\frac{80+0.65x}{80}=\frac{45}{100}$

7.

A chemist has 80 g of solution that is 65% acid. Which equation below could help you find how pure acid should be added to make a solution that is 85% acid?

a)

$0.65\cdot80+x=0.85\left(80+x\right)$

b)

$0.65x+80=0.85\left(80+x\right)$

c)

$80x+0.65\cdot80=0.85\left(80+x\right)$

d)

$0.85\cdot80+x=0.65\left(80+x\right)$

8.

A chemist has 80 g of solution that is 65% acid. How much pure acid should she add to this solution in order for it to become 90% acid?

a)

200 g.

b)

106.7 g.

c)

100 g.

d)

86.7 g.

9.

What amount of 20% salt solution should be mixed with some 8% salt solution to make 500 ml of a 15% salt solution?

a)

291.7 ml

b)

208.3 ml

c)

216.9 ml

d)

242.8 ml

10.

Which equation could help you find how much 20% salt solution should be mixed with some 8% salt solution to make 500 ml of a 15% salt solution?

a)

$0.2x+0.08\left(500-x\right)=500\cdot0.15$

b)

$0.2x+0.8\left(500-x\right)=500\cdot0.15$

c)

$0.2x+0.08\left(x-500\right)=500\cdot0.15$

d)

$0.2x+0.8\left(x-500\right)=500\cdot0.15$

11.

Jason has 20 ounces of a 50% of salt solution. How much salt should he add to make it a 75% salt solution?

a)

5 oz.

b)

10 oz.

c)

15 oz.

d)

20 oz.

12.

How much 30% acid solution should be mixed with some 18% acid solution to produce 300 ml of a 21% acid solution?

a)

75 ml

b)

225 ml

c)

90 ml

d)

210 ml

13.

Tabitha is mixing bags of trail mix. She has ten pounds of a mix that is 70% peanuts by weight.

How many pounds of a mix that is 30% peanuts by weight should she add to this original mix to create a new mix that is 40% peanuts by weight?

a)

30 lbs.

b)

40 lbs.

c)

70 lbs.

d)

110 lbs.

14.

A 50 ml bottle of after-shave lotion that is 30% alcohol by volume is mixed with 30 ml of pure water.

What is the percentage of alcohol by volume in the new solution?

a)

18.75%

b)

6.25%

c)

3.75%

d)

12.25%

15.

A 10-pound bag of trail mix is 20% chocolate by weight. Jeremy adds 2 lbs. of chocolate chips to this mix.

What percent of chocolate by weight does the mix have after the chips are added? Round to the nearest percent if necessary.

a)

33%

b)

40%

c)

27%

d)

22%

16.

Two high schools are merging. The first high school has 1600 students, of whom 25% are athletes. The second high school has 1200 students, of whom 40% are athletes.

What percentage of students in the merged high school will be athletes? Round to the nearest tenth of a percent.

a)

31.4%

b)

31.8%

c)

32.5%

d)

32.7%

17.

A 200 ml vial of saline solution is 13% salt by volume. How much pure water must be added to this solution to reduce it to 8% salt by volume?

a)

125 ml

b)

75 ml

c)

50 ml

d)

150 ml

18.

A 16-ounce box of Raisin Bran is 18% raisins by weight.

Which of these equations could help you find how many ounces of raisins must be added to this box so that the cereal is 25% raisins by weight?

a)

$0.18\cdot16+x=0.25\left(16+x\right)$

b)

$16+0.18x=0.25\left(16+x\right)$

c)

$0.18\cdot16+x=0.25\left(16-x\right)$

d)

$16+0.18x=16+0.25x$

19.

A 6-lb. bag of trail mix contains peanuts, raisins and chocolate in a weight ratio of 5:3:1.

How much more chocolate must be added so that the mix is 20% chocolate by weight?

a)

2/3rds of a lb.

b)

1/9th of a lb.

c)

5/13ths of a lb.

d)

1/6th of a lb.

20.

A mixture of 50 coins is worth $11.00. If there are only quarters and dimes in this mixture, what percent of the coins are quarters?

a)

80%

b)

40%

c)

44%

d)

72%

Mixture Problems (Algebra)

Total questions: 20

Worksheet time: 5hrs 0mins

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