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WorksheetsESG360 Week 2
Total questions: 11
Worksheet time: 10mins
For the FBD shown, the moment about A due to the 9.81kN force is calculated by
-9.81 kN x 2 m
+9.81 kN x 4 m
+9.81 kN x 2 m
-9.81 kN x 6 m
For the FBD shown, the moment about B due to the 9.81kN force is calculated by
-9.81 kN x 2 m
+9.81 kN x 4 m
+9.81 kN x 2 m
-9.81 kN x 1.5 m
For the FBD shown, the moment about B due to the Ax force is calculated by
-Ax x 1.5 m
-Ax x 2 m
-Ax x 4 m
Ax x 1.5 m
For the FBD shown, the moment about B due to the Ay force is
-Ay x 1.5 m
-Ay x 2 m
Ay x 1.5 m
0
For the FBD shown, Ay must act
in the positive y direction
in the negative y direction
For the FBD shown, if Bx is positive, then Ax...
is negative
is positive
For the beam shown, there is a roller at A and a pin at B. This means...
There is no Ax force at A
Pick the other answer
For the beam shown, there is a roller at A and a pin at B. This means that at point B:
There are forces in both the x and y-direction
There is a force only in the y-direction
There is a force only in the x-direction
There are no forces at point B
For the beam shown, the moment about B due to force P is
Counterclockwise
Clockwise
For the beam shown, the moment about B due to the 6-kips forces is
Counterclockwise
Clockwise
You are visited by a mythical beast, the Unit-corn. She reminds you never to draw masses on FBDs.
Yes, Unit-corn.
I got it, Unit-corn.
Okay, Unit-corn!
Great, thanks, Unit-corn!
