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WorksheetsHEAT: Manipulating latent heat equations
Total questions: 11
Worksheet time: 6mins
This formula is used to find the amount of heat (energy) neccesary when there's a phase change
Q= (h)(ΔT)
Q=(m)(L)
Q=(m)(c)(ΔT)
Q=(k)(A)(dT)
What is the formula to calculate specific latent heat of vaporisation?
L = Q/m
c = Q/(mΔƟ)
Q = mcΔƟ
Q = mL
the symbol for specific latent heat is
c
L
Q
m
How much heat is needed to change 12 grams of ice at 0 ºC to 12 grams of water at 0ºC? Heat of fusion = 334 kJ/kg; Specific heat of water = 4186 J/kgoC
Q = 12 x 4186 x 0
Q = 12 x 334
Q = 12000 x 334
Q = 0.012 x 334
How much heat must be lost to change of 110 grams of water at 0 ºC to 110 grams of ice at 0ºC? Heat of fusion = 334 kJ/kg; Specific heat of water = 4186 J/kgoC
Q = 110 x 4186
Q = 110000 x 4186
Q = 0.110 x 334
Q = 110 x 334
If the specific heat of water is 4,186 J/kg°C, how much heat is required to increase the temperature of 1.2 kg of water from 23 °C to 39 °C?
Q = 1.2 x 4186
Q = 1.2 x 4186 x 7
Q = 1.2 x 4186 x 17
Q = 0.0012 x 4186 x 17
