WorksheetsSystems of Equations Review
Total questions: 16
Worksheet time: 1hrs 20mins
Name
Class
Date
1.
How many solutions?
a)
One Solution
b)
No solution
c)
Infinitely Many Solutions
2.
What is the solution?
a)
1
b)
-2
c)
(1, 2)
d)
(1, -1)
3.
What is the solution to the system?
a)
(0, 3)
b)
(1, -1)
c)
(-3, 1)
d)
(1, 3)
4.
What is the number of solutions to the system of equations?
a)
No Solution
b)
Infinitely Many Solutions
c)
One Solution
d)
Two Solutions
5.
How many solutions are there in the system of equations?
a)
No Solution
b)
Infinitely Many Solutions
c)
One Solution
d)
Two Solutions
6.
What is the solution to the system of equations?
a)
(-1, -3)
b)
(3, 1)
c)
(1, 3)
d)
(-3, -1)
7.
What is the solution to this system?
x= 7 - 2y
2x + y = 5
x= 7 - 2y
2x + y = 5
a)
(-1,4)
b)
(4,-1)
c)
(1,3)
d)
(3,1)
8.
Solve:
y=8x+1
y=6x+3
y=8x+1
y=6x+3
a)
(1, 9)
b)
(4, 14)
c)
(0, 1)
d)
(2, 4)
9.
Solve:
y = 4x - 10
y = 3x - 5
y = 4x - 10
y = 3x - 5
a)
(7 , -15)
b)
(1, -5)
c)
(5 , 10)
d)
(1, 2)
10.
There are 15 animals in a barn. These animals are horses and chickens. There are 44 legs in all. Which system of equations represents the situation?
a)
x + y = 15
4x + 2y = 44
4x + 2y = 44
b)
4x + 2y = 15
x + y = 44
x + y = 44
c)
x = 2y + 44
4x = y + 15
4x = y + 15
d)
2x - 4y = 44
x - y = 15
x - y = 15
11.
Last season two running backs on the Steelers football team rushed a combined total of 1550 yards. One rushed 4 times as many yards as the other. Let x and y represent the number of yards each individual player rushed. Which system of equations could be used?
a)
x + y = 1550
y = 4x
y = 4x
b)
x + y = 1550
y = x + 4
y = x + 4
c)
y - x = 1550
y = 4x
y = 4x
d)
y = 1550 + x
y = x + 4
y = x + 4
12.
Is (3,3) a solutions to
2x+y=6
x+y=6
a)
yes
b)
no
13.
Is (2,12) a solution to
x+y=14
2x+y=16
a)
yes
b)
no
14.
What is the slope of this equation?
y = 3x - 4
y = 3x - 4
a)
3
b)
-4
c)
3x
d)
4
15.
What is the y-intercept of this equation?
y = 5x + 8
y = 5x + 8
a)
(0, 5)
b)
(5, 0)
c)
(0, 8)
d)
(8, 0)
16.
Calculate the slope.
a)
m= -2
b)
m=-1/2
c)
m=2
d)
m=1/2
100 %
