Free Printable 0-9 to 8-6 Quiz

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0-9 to 8-6 Quiz

Total questions: 16

Worksheet time: 4hrs 0mins

Name

Class

Date

Select all the correct answers that explain the difference when finding the standard deviation of a population compared to that of a sample.

We use $\mu$ instead of $\overline{X}$ when talking about the population mean instead of the sample mean.

We use $s$ instead of $\sigma$ when talking about the sample standard deviation instead of the population standard deviation.

We divide by $n-1$ instead of $n$ when finding the sample standard deviation instead of the population standard deviaiton.

None of these are correct.

Given the data set below. What is the five number summary?

4, 6, 9, 2, 11, 7, 14, 8, 10

Min: 2 Q1: 5 Med: 8 Q3: 10 Max: 14

Min: 4 Q1: 6 Med: 8 Q3: 10.5 Max: 11

Min: 2 Q1: 6 Med: 9 Q3: 11 Max: 14

Min: 2 Q1: 5 Med: 8 Q3: 10.5 Max: 14

10 random students were given a survey to take during lunchtime out of all the students. They were asked how many enriched classes they were going to take the next year. Find the standard deviation for the amount of enriched classes the students are going to take next year to two decimal places.

0, 3, 2, 1, 4, 0, 1, 2, 1, 3

(a)

Given the histogram, what type of distribution does the data set have?

Negatively Skewed

Symmetric

Positively Skewed

With the histogram above, should we use the sample mean and sample standard deviation or 5-Number-Summary to describe our data?

5-Number-Summary

Sample Mean and Sample Standard Deviation

Class A and Class B both took the same quiz. There results for every student in both classes are below along with the box-and-whisker plot for each class. Should we use the 5-Number-Summary or the Population Mean and Standard Deviation to describe this data. What description fits the data?

Population Mean and Standard Deviation.

5-Number-Summary

Explain why the bar graph is or is not misleading.

4 lines

Choose the best explanation of why the conclusion presented in the following report is valid or not.

The report is based on the results of a survey, so it may be valid.

The report is based on the results of an observational study, so it may not be valid.

The report is based on the results of an observational study, so it may be valid.

The report is based on the results of a survey, so it may not be valid.

For a normal distribution, the population mean $\mu=77.8$ and the standard deviation $\sigma=8.8$ . What percent of the data will be less than 86.6?

2.5%

97.5%

16%

84%

10.

A 12 oz can of soda has a mean volume of 12 oz, with a standard deviation of .25 oz. How common are cans with less than 11.5 oz of soda? Calculate the probability.

2.28%

34.46%

2.51%

2.17%

11.

Using the empirical rule, what percentage of data lies between $\mu-2\sigma$ and $\mu+2\sigma$ ?

(a)

12.

Give the mean and median of the data set below:

10, 8, 18, 17, 15, 12, 9, 21, 14, 16

mean: 15, median: 15

mean: 14, median: 14.5

mean: 14, median: 14

mean: 14.5, median 14

13.

For the given data set, state the outliers. If there is more than one have them in a list separated by commas. If there are no outliers give the answer N/A.

23, 31, 33, 37, 40, 41, 11, 34, 59, 26, 49, 34, 38, 28

(a)

14.

If $\mu=1200$ and $\sigma=140$ . Find $P\left(X<1000\right)$

7.64%

9.18%

7.21%

12.71%

15.

What is the correct formula to find a z-score?

$z=\frac{X-\mu}{\sigma}$

$z=\frac{X-\sigma}{\mu}$

$z=\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}}$

$z=\frac{\Sigma\left(x-\overline{x}\right)^2}{n}$

16.

Write out in words how you would find $P\left(X>120\right)$ given you know that $\mu=127$ and $\sigma=11$ .

4 lines

100 %

0-9 to 8-6 Quiz

Total questions: 16

Worksheet time: 4hrs 0mins

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