WorksheetsDPC1033 CHAPTER 5 SOLUTION
Total questions: 21
Worksheet time: 5hrs 15mins
What is the molality of a solution when 48 g of NaCl is dissolved in 5 kg of water?
557 m
4.14 m
.17 m
6.04 m
How many mL of stock solution of 2M NaCl do you need to prepare 100 mL of 0.150M NaCl?
7.5 mL
15 mL
1333 mL
200 mL
Calculate the Molarity in a solution containing 40.0 g of NaCl dissolved in 500.0 ml of H2O.
0.08 M
12.5 M
1.37 M
0.74 M
Zn(OH)2 + HNO3 ---> H2O + Zn(NO3)2
Diagram 1 shows the set-up of apparatus for the titration of potassium hydroxide solution with sulphuric acid.
What is the total volume of the mixture in the conical flask at the end point of the titration in Diagram 1if the concentration of sulphuric acid is 1.0 moldm-3 ?
10 cm3
20 cm3
30 cm3
40 cm3
The equation shows the reaction between sulphuric acid and sodium hydroxide.
H2SO4 + 2NaOH ---------- Na2SO4 + 2H2O
What is the volume of 1.0 mol dm-3 sodium hydroxide solution which can neutralize 25.0 cm3 of 1.0 mol -3 sulphuric acid?
12.5 cm3
25.0 cm3
50.0 cm3
75.0 cm3
