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a=\sqrt{a}=a=
a12a^{\frac{1}{2}}a21
a21a^{\frac{2}{1}}a12
a2\frac{a}{2}2a
a2=\sqrt{a^2}=a2=
2a\sqrt{2a}2a
aaa
aaa\sqrt{a}aa
a13a^{\frac{1}{3}}a31
3a3a3a
a31a^{\frac{3}{1}}a13
Això és teoria. Totes les respostes són vàlides.
a54a^{\frac{5}{4}}a45
2
8
6
4
24
83\frac{8}{3}38
-2
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