Worksheets4/23/2020 Compound Area Problems
Total questions: 13
Worksheet time: 1hrs 1mins
Name
Class
Date
1.
What is the area of the composite figure?
a)
80 cm2
b)
16 cm2
c)
96 cm2
d)
32 cm2
2.
Find the area of the shaded region:
a)
350 cm2
b)
137.5 cm2
c)
212.5 cm2
d)
484.2 cm2
3.
Find the area
a)
150m2
b)
120m2
c)
126m2
d)
200m2
4.
What is the area of the shaded region?
a)
4 cm2
b)
16 cm2
c)
8 cm2
d)
12 cm2
5.
Calculate the area of the figure.
a)
468 meters squared
b)
754 meters squared
c)
611 meters squared
d)
1222 meters squared
6.
Find the area of the compound shape. Give your answer to 1 decimal place...
a)
26.1cm2
b)
125.1cm2
c)
68.5cm2
d)
28.3cm2
7.
Find the area of the compound shape. Give your answer to 1 decimal place... HINT: You are adding a rectangle and HOW MUCH of a circle?
a)
58.3cm2
b)
143.1cm2
c)
86.5cm2
d)
67.7cm2
8.
Find the area of the shaded region using the formulas.
a)
(4 x 8) + (3.14 x 12)
b)
(3.14 x 12) - (4 x 8)
c)
(4 x 8) - (3.14 x 22)
d)
(4 x 8) - (3.14 x 12)
9.
Find the composite area.
a)
6.28
b)
24
c)
40
d)
38.28
10.
Find the area of the shape
a)
44.13 sq cm
b)
143.04 sq cm
c)
88.26 sq cm
11.
2. The figure shows a circle inside a triangle. Which equation could be used to find the area of the shaded region?
a)
A = ½bh - 2πr
b)
A = πr² - ½bh
c)
A = ½bh - πd
d)
A = ½bh - πr²
12.
6. The figure shows 2 circles inside a trapezoid.
Which procedure should be used to find the area of the shaded region?
Which procedure should be used to find the area of the shaded region?
a)
Subtract the perimeter of the trapezoid from the area of both circles.
b)
Subtract the circumference of both circles from the area of the trapezoid.
c)
Subtract the area of the trapezoid from the area of both circles.
d)
Subtract the area of both circles from the area of the trapezoid.
13.
11. A company’s logo is formed by drawing a circle and then replacing the two opposite quarter circles with squares as shown.
What is the approximate area of the logo?
What is the approximate area of the logo?
a)
46 cm2
b)
32 cm2
c)
71 cm2
d)
85 cm2
100 %
