WorksheetsCalculus Motion Basics
Total questions: 26
Worksheet time: 49mins
Position and velocity are graphed here. Which is which?
blue is position, red is velocity
red is position, blue is velocity
There is not enough information to determine
As derivative of position, red is velocity, cm/sec, of a particle moving on a horizontal line. What is the particle doing from 0 to 2 seconds? Do not choose the graph. It's showing speed and FYI.
slowing down, moving forward (right)
slowing down, moving backward (left)
speeding up, moving backward
speeding up, moving forward
These are graphs for the motion of a particle on a horizontal line. Which of these is the best description of their relationship?
velocity is the absolute value of speed
speed is the absolute value of velocity
velocity is stronger than speed
speed wants nothing to do with velocity
These are graphs for the motion of a particle on a horizontal line. On what intervals is the particle speeding up? (Speed is increasing) Check all that apply.
(0,1)
(1,2)
(2,3)
(3,4)
(4,6)
Find the average velocity from t = 3 to t = 5.
Given the graph of the position function, which graph below shows the velocity of the function?
Using s(t) as position and a(t) as acceleration, this integral is equal to s(5) – s(1). This represents ___________________. Check all that apply.
change of position
displacement
position at 5 minus position at 1
distance traveled over a 4 second period
microwave settings
Which of these represents velocity of this position function?
sqrt( 3(x2) + 1)
sqrt( (3x)2 + 1)
(2x)sqrt( 3(x2) + 1)
none of these
Speed
v(t) > 0
a(t) > 0
∣v(t)∣
∣a(t)∣
Given this velocity graph, speed is
Increasing, Positive
Increasing, Negative
Decreasing, Positive
Decreasing, Negative
Given this velocity graph, the acceleration of the particle is
Positive, Increasing
Positive, Decreasing
Negative, Increasing
Negative, Decreasing
An object is speeding up when
v(t) > 0
a(t) > 0
v(t) and a(t) are the same sign
v(t) and a(t) are different signs
This graph is velocity of a particle moving on a horizontal number line with initial position at -5, s(0) = -5. What is the particle doing from 0 to 2 seconds?
moving down
moving right
moving left
moving out
This graph is velocity, cm/sec, of a particle moving on a horizontal number line with initial position at -5, s(0) = -5. From 0 to 2, the particle moves backward. From 2 to 4, the particle moves forward. After 4 seconds, is the particle to the left or right of -5 on the number line?
left a smidge
right a smidge
There is not enough information to determine
why is this particle the object of our quandary?
Red is velocity, cm/sec, green is speed. Particle motion on horizontal line. What is the total distance traveled from 0 to 2 seconds?
8 cm
4 cm
4 cm2
cannot be determined
Displacement of a particle is different than distance traveled.
always true
sometimes true
never true
only on Tuesdays
Adding up area between the red curve and the x-axis gives
displacement
distance traveled
position at 6
nothing special
Using s(t) as position and v(t) as velocity, distance traveled would be
∫06s(t) dt
∫06v(t)dt
∫06∣s(t)∣dt
∫06∣v(t)∣dt
Which of these is integrating speed?
∫06s(t) dt
∫06v(t)dt
∫06∣s(t)∣dt
∫06∣v(t)∣dt
