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Chapter 10. Three-Dimensional Vectors (Con't)

Total questions: 17

Worksheet time: 1hrs 25mins

Name
Class
Date
1.

Given vector a and b respectively,  a=i+4j7k\overrightarrow{a}=i+4j-7k  and  b=5i2j3k\overrightarrow{b}=5i-2j-3k  . The vectors are placed tail to tail.

Find the dot product of a.b.


(a)  

2.

Given vector a and b respectively,  a=i+4j7k\overrightarrow{a}=i+4j-7k  and  b=5i2j3k\overrightarrow{b}=5i-2j-3k  . The vectors are placed tail to tail.

Find the angle between a and b. (round it to the nearest thousandth degree)


(a)  

3.

Given vector a and b respectively,  a=i+4j7k\overrightarrow{a}=i+4j-7k  and  b=5i2j3k\overrightarrow{b}=5i-2j-3k  . The vectors are placed tail to tail.

Find the dot product of b.a


(a)  

4.

Given vector a and b respectively,  a=i+4j7k\overrightarrow{a}=i+4j-7k  and  b=5i2j3k\overrightarrow{b}=5i-2j-3k  . The vectors are placed tail to tail.

Selects all that apply about magnitude a or b.

a)

|a|= √66

b)

|b| =  4

c)

|a| =  √32

d)

|b| =  38

e)

|a| =  66

5.

Given vector a and b respectively, a=i+4j7k\overrightarrow{a}=i+4j-7k  and b=5i2j3k\overrightarrow{b}=5i-2j-3k . The vectors are placed tail to tail.

Find p, scalar projection of vector a on b. (round it to nearest hundredth)


(a)  

6.

Given vector a and b respectively,  a=i+4j7k\overrightarrow{a}=i+4j-7k  and  b=5i2j3k\overrightarrow{b}=5i-2j-3k  . The vectors are placed tail to tail.

Find  p\overrightarrow{p}  , vector projection of vector a on b.

a)

 p=2.345i0.671j1.364k\overrightarrow{p}=2.345i-0.671j-1.364k  

b)

 p=2.368i0.974j1.124k\overrightarrow{p}=2.368i-0.974j-1.124k  

c)

 p=2.368i0.947j1.421k\overrightarrow{p}=2.368i-0.947j-1.421k  

d)

 p=4.368i0.974j1.124k\overrightarrow{p}=4.368i-0.974j-1.124k  

7.

Given vector a and b respectively,  a=i+4j7k\overrightarrow{a}=i+4j-7k  and  b=5i2j3k\overrightarrow{b}=5i-2j-3k  . The vectors are placed tail to tail.

Find cross product of these two vectors,  a×b\overrightarrow{a}\times\overrightarrow{b} 

a)

-25i - 31j - 23k

b)

-26i - 32j - 22k

c)

-26i + 32j + 23k

d)

26i + 32j - 22k

8.

Given vector a and b respectively,  a=i+4j7k\overrightarrow{a}=i+4j-7k  and  b=5i2j3k\overrightarrow{b}=5i-2j-3k  . The vectors are placed tail to tail.

Find cross product of these two vectors,  b×a\overrightarrow{b}\times\overrightarrow{a} 

a)

25i + 31j + 23k

b)

26i + 32j + 22k

c)

26i + 31j + 23k

d)

-26i - 32j + 22k

9.

Given vector a and b respectively,  a=i+4j7k\overrightarrow{a}=i+4j-7k  and  b=5i2j3k\overrightarrow{b}=5i-2j-3k  . The vectors are placed tail to tail.

Find the area of parallelogram formed by these two vectors. (round it to the nearest thousandth unit-square)


(a)  

10.

Consider vector a and b,  a=2i+5j3k\overrightarrow{a}=2i+5j-3k  and  b=7i4j2k\overrightarrow{b}=7i-4j-2k 
. Select one that apply.

a)

vector a and vector b are parallel to each other,

b)

vector a and vector b are perpendicular to each other

c)

vector a and vector b form a certain value of angle between 0 to 90 degrees

d)

vector a and vector b form a certain value of angle between 90 to 180 degrees.

11.

Consider vector a and b,  a=3i+6j12k\overrightarrow{a}=-3i+6j-12k  and  b=5i10j+20k\overrightarrow{b}=5i-10j+20k 
. Select one that apply.

a)

vector a and vector b are parallel to each other,

b)

vector a and vector b are perpendicular to each other

c)

vector a and vector b form a certain value of angle between 0 to 90 degrees

d)

vector a and vector b form a certain value of angle between 90 to 180 degrees.

12.

Consider vector a,  a=5i+3j+7k\overrightarrow{a}=5i+3j+7k . Find the direction angles for vector a.

a)

 α=56.713°, β=39.794°, γ=70.774°\alpha=56.713\degree,\ \beta=39.794\degree,\ \gamma=70.774\degree  

b)

 α=56.714°, β=70.774°, γ=39.794°\alpha=56.714\degree,\ \beta=70.774\degree,\ \gamma=39.794\degree  

c)

 α=59.714°, β=36.794°, γ=70.774°\alpha=59.714\degree,\ \beta=36.794\degree,\ \gamma=70.774\degree  

d)

 α=36.794°, β=59.714°, γ=70.774°\alpha=36.794\degree,\ \beta=59.714\degree,\ \gamma=70.774\degree  

13.

If a vector has α=152° \alpha=152\degree\   and  β=73°\beta=73\degree  , find  cos2γ\cos^2\gamma . (round it to the nearest thousandth)

(a)  

14.

Find the equation of the plane containing the point (3, 5, 7) with normal vector  n=11i+2j+13k\overrightarrow{n}=11i+2j+13k  

a)

 (3+11294d)i\left(3+\frac{11}{\sqrt{294}}d\right)i  + (5+2294d)j\left(5+\frac{2}{\sqrt{294}}d\right)j  + (7+13294d)k\left(7+\frac{13}{\sqrt{294}}d\right)k  

b)

11x + 2y + 13z = 134

c)

3x + 5y + 7z = 134

d)

none of answers are correct

15.

Find a vector   n\overrightarrow{n}  normal to the plane 7x - 3y + 8z = 51 .. 

a)

 n=7122i\overrightarrow{n}=\frac{7}{\sqrt{122}}i   3122j-\frac{3}{\sqrt{122}}j   +8122k+\frac{8}{\sqrt{122}}k  

b)

 n=7i+3j+8k\overrightarrow{n}=7i+3j+8k  

c)

 n=7i+3j8k\overrightarrow{n}=-7i+3j-8k  

d)

can't be solved because lack of information

16.

A line containing the point (5, 3, -1) has direction cosines c1=611   c2=211 and   c3=911c_1=\frac{6}{11}\ \ \ c_2=\frac{-2}{11}\ and\ \ \ c_3=\frac{9}{11}  . Find the particular equation of the line.

a)

 r=(5+611d)i\overrightarrow{r}=\left(5+\frac{6}{11}d\right)i  + (3211d)j\left(3-\frac{2}{11}d\right)j  + (1+911d)k\left(-1+\frac{9}{11}d\right)k  

b)

 r=(5d)i+(3d)j1dk\overrightarrow{r}=\left(5d\right)i+\left(3d\right)j-1dk  

c)

 r=(6111d)i\overrightarrow{r}=\left(\frac{61}{11}d\right)i   +(3111d)j+\left(\frac{31}{11}d\right)j   +(211d)k+\left(\frac{2}{11}d\right)k  

d)

 r=(611d)i\overrightarrow{r}=\left(\frac{6}{11}d\right)i   +(211d)j+\left(-\frac{2}{11}d\right)j   +(911d)k+\left(\frac{9}{11}d\right)k  

e)

No right answers

17.

A line containing the point (5, 3, -1) has direction cosines c1=611   c2=211 and   c3=911c_1=\frac{6}{11}\ \ \ c_2=\frac{-2}{11}\ and\ \ \ c_3=\frac{9}{11}  . Find the point where the line intersects the plane 7x + 4y - 2z = 39.

a)

 r=1.25i+4.25j+6.625k\overrightarrow{r}=1.25i+4.25j+6.625k  

b)

 r=1.25i+4.25j6.625k\overrightarrow{r}=1.25i+4.25j-6.625k  

c)

 r=1.25i4.25j+6.625k\overrightarrow{r}=1.25i-4.25j+6.625k  

d)

 r=1.25i+4.25j6.625k\overrightarrow{r}=-1.25i+4.25j-6.625k  

e)

No right answers