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WorksheetsPre-U Electromagnetism
Total questions: 19
Worksheet time: 25mins
There are several ways to induce an e.m.f. in a conductor. Which one of these will not work?
Move a wire around a magnet
Place a strong magnet next to a coil
Increase the strength of a magnetic field near a coil
Move a magnet in and out of a coil
The magnetic flux cutting through a loop of wire is defined as
area of loop parallel to the field x magnetic field strength
area of loop perpendicular to the field x magnetic field strength
length of wire parallel to the field x magnetic field strength
length of wire perpendicular to the field x magnetic field strength
Magnetic flux is measured in
teslas
coulombs
webers
farads
"The direction of the induced current in a conductor will be in such a direction so as to oppose the change in flux that created it." This law is called
Lenz's Law
Faraday's Law
Planck's Law
Tesla's Law
The magnitude of the e.m.f. induced in a conductor is proportional to
the change in the flux
the rate of change of flux
the change in the field strength
the rate of change of field strength
The diagram shows a long wire placed in a magnetic field directed out of the screen. Which on of these answers correctly describes the direction of the induced current in the wire when it is moved upwards, and to the right?
Moved upwards: Current to the right
Moved to the right: Current to the left
Moved upwards: No current
Moved to the right: Current to the right
Moved upwards: Current to the right
Moved to the right: No current
Moved upwards: Current to the left
Moved to the right: No current
In the diagram, if the field strength is B and the wire of length l is moved with a velocity v, the maximum induced e.m.f. will be E. The experiment is repeated with a shorter wire of length l/4 and moved at a velocity of 3v. To induce the same e.m.f. in the wire the magnetic field strength must be
12B
B/12
4B/3
3B/4
A coil is rotated at a constant frequency f inside a magnetic field. The induced e.m.f. generated in the coil is shown in this diagram. The peak e.m.f. is E.
Which of these four diagrams shows the induced e.m.f. when the coil is rotated at a frequency of 2f?
The r.m.s. voltage induced in a coil when rotated at a higher frequency of 2f is
2E
E√2
E
E / √2
A transformer has 100 primary windings and 2000 secondary windings. The input (r.m.s.) voltage on the primary coil is 12 V and the input current is 10 A.
What will the output voltage and current be?
A
B
C
D
No transformer is 100% efficient. Which one of these could not account for a loss of energy?
Magnetic flux linkage is not complete between the two coils
Heat loss in the coils
The current is reduced in proportion to the increases in voltage
The iron core gains internal energy as the magnetic field varies
A high voltage transmission line operating at 10 000 V carrying a current of 10 A is compared to a low voltage system operating at 100 V but delivering the same power to the cables and load.
Over cables with a small fixed resistance, the ratio of power loss in the low voltage cable to the high voltage cable will be
10 000 : 1
1000 : 1
100 : 1
10 : 1
In the generator shown a coil rotates inside a magnetic field. Which of these factors will not affect the peak e.m.f. of the output of the generator?
The direction of rotation of the coil
The strength of the magnetic field
The length of the wire coil inside the field
The frequency of rotation
The output of this generator is...
a.c. and rectified
a.c. and not rectified
d.c. and rectified
d.c. and not rectified
At one point in the rotation of a simple generator, the e.m.f. output is zero. Which of these answers states and explains where and why this occurs?
when the coil is vertical because the flux linkage is zero
when the coil is vertical because the rate of change of flux linkage is zero
when the coil is horizontal because the flux linkage is zero
when the coil is horizontal because the rate of change of flux linkage is zero
An a.c. supply is connected to a bulb. A diode bridge network is used to produce a current flowing in one direction only.
Which of the diagrams below correctly shows the diode bridge? The current must flow through the bulb in the direction shown by the red arrows.
A
B
C
D
A simple way of turning an a.c. supply into a d.c. supply is using just 2 components. One acts as a half wave rectifier and the other smooths the output.
The two components needed are...
A
B
C
D
A horizontal, current-carrying wire is placed in the magnetic field between two opposite magnetic poles. The arrow on the diagram shows the direction of the current in the wire.
The wire experiences a force.
In which direction does this force act?
Horizontally to the left
Horizontally to the right
Vertically downwards
Vertically upwards
An electron, travelling in a straight line at 1.46 x 107 ms-1, enters a region where there is a uniform magnetic field.
The diagram shows the path followed by the electron before it enters the magnetic field and within the field.
In the magnetic field, the electron follows a semi-circular path of diameter 0.0700 m.
In which direction is the magnetic field and what is the size of the magnetic flux density?
Direction of magnetic field: into screen
Size of magnetic flux density: 1.19 x 10-3 T
Direction of magnetic field: into screen
Size of magnetic flux density: 2.38 x 10-3 T
Direction of magnetic field: out of screen
Size of magnetic flux density: 1.19 x 10-3 T
Direction of magnetic field: out of screen
Size of magnetic flux density: 2.38 x 10-3 T
