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Basic maths for physics

Total questions: 16

Worksheet time: 8mins

Name
Class
Date
1.

Using Binomial approximation, the value of  82\sqrt{82}  is

a)

 9+1169+\frac{1}{16}  

b)

 9+1189+\frac{1}{18}  

c)

 9+1229+\frac{1}{22}  

d)

 9+1149+\frac{1}{14}  

2.

Refer to the equation given below. If x is very small compared to a then y  will be approximately equal to
 y=1(8a3x3)231(8a3+x3)23y=\frac{1}{\left(8a^3-x^3\right)^{\frac{2}{3}}}-\frac{1}{\left(8a^3+x^3\right)^{\frac{2}{3}}}  

a)

 3x32a5\frac{3x^3}{2a^5}  

b)

 x320a5\frac{x^3}{20a^5}  

c)

 x324a5\frac{x^3}{24a^5}  

d)

 2x33a5\frac{2x^3}{3a^5}  

3.

Simplify the following using Binomial approximation
 7013\lfloor\sqrt{70}\rfloor^{\frac{1}{3}}  

a)

 2.0312.031  

b)

 2.1312.131  

c)

 8.0318.031  

d)

 4.0314.031  

4.

The value of  1200\frac{1}{\sqrt{200}}  is same as

a)

 0.750.75  

b)

 0.650.65  

c)

 0.70.7  

d)

 0.070.07  

5.

The rate of flow of liquid (I) in a tube of radius r and length l due to a pressure difference P is given by  I=π8η Plr4I=\frac{\pi}{8\eta}\ \frac{P}{l}r^4  Here  η\eta  is called coefficient of viscosity.  If Pressure increases by 4%, length decreases by 2%,  radius increases by 1.5%  and coefficient of viscosity increases by 0.5%, find the percentage change in rate of flow

a)

11.5%

b)

11%

c)

8.5%

d)

8%

6.

The mass and radius of a spherical object are 40 g and 4 cm respectively. if mass reduces by 2 g and radius increases by 4 mm then the percentage change in density is given by

a)

35%

b)

-35%

c)

-25%

d)

25%

7.

The angle subtended by a pole with the horizontal is  4421\frac{44}{21} radian. Its value of the angle in degree is given by 

a)

 90090^0  

b)

 75075^0  

c)

 1200120^0  

d)

 1800180^0  

8.

The value of  5π3\frac{5\pi}{3} radian in degree is given by

a)

120

b)

180

c)

240

d)

300

9.

The value of  sinθ\sin\theta  is  23\frac{2}{3}  then find the value of  secθ\sec\theta  

a)

 53\frac{\sqrt{5}}{3}  

b)

 25\frac{2}{\sqrt{5}}  

c)

 35\frac{3}{\sqrt{5}}  

d)

 15\frac{1}{\sqrt{5}}  

10.

A shadow of a pencil of length 10 cm is formed on the desk as shown in the figure. If the length of the shadow is 6 cm then the angle made the pencil wit the floor is

a)

60060^0

b)

37037^0

c)

53053^0

d)

45045^0

11.

If   θ\theta  is  2π3\frac{2\pi}{3}  then the value of y given by the relation below    is       y=(4sin2θ2cosθtan22θ)cotθ\ \ y=\frac{\left(4\sin^2\theta-2\cos\theta-\tan^22\theta\right)}{\cot\theta}  

a)

 2\sqrt{2}  

b)

 3\sqrt{3}  

c)

 13\frac{1}{\sqrt{3}}  

d)

 33  

12.

The correct expression for  tan(a+b)\tan\left(a+b\right) . Hint: use the knowledge of  sin (a+b) and cos (a+b)\sin\ \left(a+b\right)\ and\ \cos\ \left(a+b\right)   

a)

 tana tanb1+(tana)(tanb)\frac{\tan a\ -\tan b}{1+\left(\tan a\right)\left(\tan b\right)}  

b)

 tana +tanb1(tana)(tanb)\frac{\tan a\ +\tan b}{1-\left(\tan a\right)\left(\tan b\right)}  

c)

 tana tanb1(tana)(tanb)\frac{\tan a\ \tan b}{1-\left(\tan a\right)\left(\tan b\right)}  

d)

 tana +tanb(tana)(tanb)\frac{\tan a\ +\tan b}{\left(\tan a\right)-\left(\tan b\right)}  

13.

  tan (180θ)\tan\ \left(180-\theta\right)  is

a)

 tanθ\tan\theta  

b)

 cotθ\cot\theta  

c)

 tanθ-\tan\theta  

d)

 cotθ-\cot\theta  

14.

The approximate value of  sin(40)\sin\left(40\right)  

a)

 15(3+π15)\frac{1}{5}\left(3+\frac{\pi}{15}\right)  

b)

 15(32π45)\frac{1}{5}\left(3-\frac{2\pi}{45}\right)  

c)

 15(4+π30)\frac{1}{5}\left(4+\frac{\pi}{30}\right)  

d)

 15(3+π60)\frac{1}{5}\left(3+\frac{\pi}{60}\right)  

15.

Statement 1: The sin and cos of an angle is negative in third quadrant

Statement 2: The tan and sin of an angle are positive in second quadrant

Statement 3: The tan and sin of an angle are negative in fourth quadrant


Choose the correct statement

a)

statement 1, 2 and 3 are correct

b)

statement 1, 2 are correct and 3 is wrong

c)

statement 1, 3 are correct and 2 is wrong

d)

statement 1, 2 and 3 are wrong

16.

Consider  y=sinxy=\sin x . If x increases by  303^0  then the variation in y  (ie Δy)\left(ie\ \Delta y\right) for  x=600x=60^0  is  

a)

 π120\frac{\pi}{120}  

b)

 π90\frac{\pi}{90}  

c)

 π60\frac{\pi}{60}  

d)

 π50\frac{\pi}{50}