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limx→2 (−3x+1)\lim_{x\rightarrow2}\ \left(-3x+1\right)x→2lim (−3x+1)
2
-3
-5
limx→4 1(x−4)2\lim_{x\rightarrow4}\ \frac{1}{\left(x-4\right)^2}x→4lim (x−4)21
0
∞\infty∞
- ∞\infty∞
limx→3 6 \lim_{x\rightarrow3}\ \ 6\ x→3lim 6
3
6
limx→1(11−xx2 +9)=\lim_{x\rightarrow1}\left(\frac{11-x}{x^2\ +9}\right)=x→1lim(x2 +911−x)=
1
Does not exist
A
B
C
D
State the dominant term then determine the limit.
−∞-\infty−∞
−32-\frac{3}{2}−23
7
limx→3 x−3x2−9=\lim_{x\rightarrow3}\ \frac{x-3}{x^2-9}=x→3lim x2−9x−3=
16\frac{1}{6}61
غير موجودة
limx→12 (x−3)=\lim_{x\rightarrow12}\ \left(\sqrt{x-3}\right)=x→12lim (x−3)=
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10 questions
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