(x + 6)(x - 4)

(x + 4)(x - 6)

(x - 4)(x - 6))

(x - 3)(x + 8)

(x + 3)(x - 16)

(x + 16)(x - 3)

(x + 4)(x - 12)

(x + 12)(x - 4)

y=(x+2)(x-1)

y=(x-2)(x+1)

y=(x-2)(x-1)

y=(x+2)(x+1)

 $2\left(x-4\right)^2$  

 $2\left(x+4\right)\left(x-4\right)$  

 $\left(2x-8\right)\left(x-4\right)$  

 $2\left(2x+4\right)\left(x-8\right)$  

 $\left(2x+1\right)\left(4x-3\right)$  

 $\left(4x+3\right)\left(2x-1\right)$  

 $\left(8x-1\right)\left(x+3\right)$  

 $\left(4x+1\right)\left(2x-3\right)$  

 $\left(9x+1\right)\left(x-1\right)$  

 $\left(3x-1\right)^2$  

 $\left(3x-1\right)\left(3x+1\right)$  

 $\left(3x+1\right)^2$  

 $\left(2x-3\right)\left(2x+2\right)$  

 $\left(4x+3\right)\left(x-2\right)$  

 $\left(2x+3\right)\left(2x-2\right)$  

 $\left(4x-3\right)\left(x+2\right)$  

 $\left(8x+6\right)\left(x-1\right)$  

 $\left(4x+7\right)\left(x-3\right)$  

 $\left(4x-3\right)\left(x+7\right)$  

 $\left(2x+3\right)\left(2x+7\right)$  

 $\left(2x+3\right)\left(2x-7\right)$  

 $\left(2x+7\right)\left(2x-3\right)$  

Splitting the middle term

The cross method

 $\left(3x^2+5x\right)\left(x-12\right)$   $\$  

 $3x\left(x^2+8x-20\right)$  

 $\left(3x^2+4x\right)\left(x-15\right)$  

 $3x\left(x+10\right)\left(x-2\right)$  

 $3x\left(x-5\right)\left(x+4\right)$  

Most of the time

some of the time

rarely

what is a quadratic?

Fabulous

Confident

Ok - mostly

I am still really struggling

I can do monics but not non-monics