ABCD is a square and P, Q, R are points on AB, BC and CD respectively such that AP = BQ = CR and $\angle$ PQR = 90 $\degree$  , then $\angle$ QPR is

In a $\Delta$ XYZ, LM ║ YZ and bisectors YN and ZN of $\angle$ Y & $\angle$ Z respectively meet at N on LM then YL + ZM =  

In a $\Delta$ PQR, PS is the bisector of $\angle$ P and  $\angle$ Q = 70 $\degree$ ,  $\angle$ R = 30 $\degree$ , then

If D is any point on the side BC of a $\Delta$ ABC, then 

For given figure, which one is correct :

Which of the following is not a criterion for congruence of triangles?

In $\Delta$ ABC, AB = AC and $\angle$ B = 50°. Then $\angle$ C is equal to

Two sides of a triangle are of lengths 5 cm and 1.5 cm. The length of the third side of the triangle cannot be

In triangles ABC and PQR, AB = AC, $\angle$ C = $\angle$ P and $\angle$ B = $\angle$ Q. The two triangles are