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WorksheetsMA8353- TRANSFORMS AND PARTIAL DIFFERENTIAL EQUATIONS
Total questions: 125
Worksheet time: 4hrs 14mins
Pick out the even function.
sinx
tanx
x2
x3
The period of sinx is
2π
π
π/2
3π/2
The value of a0 in the Fourier series of f(x)=x in (0,2π) is
2π
π
0
−π
if f(x) is an even function, then the value of bn in the Fourier series for f(x) in (−π,π) is
(2/π)∫0πf(x)sinxdx
π
(1/π)∫−ππf(x)sinxdx
0
Which of the following function doesnot have a Fourier series in (0,2π) ?
sinx
tanx
cosx
x2
Pick out one of the conditions of Dirichlet’s condition.
f(x) has infinite number of infinite discontinuous in any one period
f(x) is infinite valued function
f(x) has infinite number of maxima and minima
if ∣f(x)∣ is even whenever f(x) is
Even only
Odd only
Neither even nor odd
Either even or odd
Which of the following function is neither even nor odd?
sinx
x2+x
cosx
x2
if f(x) is an odd function, then the value of an in the Fourier series for f(x) in (−π,π) is
(2/π)∫0πf(x)sinxdx
π
(1/π)∫−ππf(x)sinxdx
0
if f(x) is an even function, then an in the Fourier series for f(x) in (−π,π) is given by
(2/π)∫0πf(x)sinxdx
π
(2/π)∫0πf(x)cosxdx
0
The Fourier Transform of f(x) is F[f(x)]=
2π1∫−∞∞f(x) dx = F[s]
2π1∫−∞∞f(x)eisx dx = F[s]
2π1∫−∞∞f(x) ds = F[s]
2π1∫−∞∞f(x) cossx dx = F[s]
The Fourier sine Transform of f(x) is Fs[f(x)]=
2π1∫−∞∞f(x) dx = Fs[s]
2π1∫0∞f(x) sinsx dx = Fs[s]
π2∫0∞f(x) sinsx dx = Fs[s]
2π1∫−∞∞f(x) cossx dx = Fs[s]
The Fourier Sine Transform of
e−axFs[e−ax]=π2 a2+s2a
Fs[e−ax]=π2 a2+s2s
Fc[e−ax]=π2 a2+s2s
none of the above
The Fourier cosine Transform of
e−axFs[e−ax]=π2 a2+s2a
Fs[e−ax]=π2 a2+s2s
Fc[e−ax]=π2 a2+s2a
none of the above
Fc[f(x) cosax] is
21[Fs(A+S)+Fs(A−S)]
21[Fs(A+S)+Fs(A+S)]
21[Fc(A+s)+Fc(A−s)]
21[Fc(A+s)−Fc(A−s)]
Fs[f(x) cosax] is
21[Fs(a+S)−Fs(a−S)]
21[Fs(a+S)+Fs(a−S)]
21[Fc(a+s)+Fc(a−s)]
21[Fc(a+s)−Fc(a−s)]
The linear Fourier transform is
F[af+bg] =aF[s] +bG[s]
F[f⋅g] =F[s] ⋅G[s]
F[af] =∣a∣1F[as]
F[f′(x)] =−isF[s]
The Fourier Sine Transform of
e−5xFs[e−5x]=π2 52+s25
Fs[e−5x]=π2 52+s2s
Fs[e−5x]=π2 a2+s2s
none of the above
The Fourier Cosine Transform of
e−5xFc[e−5x]=π2 52+s25
Fc[e−5x]=π2 52+s2s
Fc[e−5x]=π2 a2+s25
none of the above
Fs(xf(x)) =
dsd Fc[s]
−dsd Fc[s]
dsd Fs[s]
dsd Fs[s]
The value of cos 2π and cos π
0 and 0
1 and 1
1 and -1
-1 and -1
The Fourier series is a combination of -----and ---- trigonometric terms
sine and co secant
tangent and cotangent
sine and cosine
cosine and secant
Identify Even function from the following
x+x2
x2 + x3
x2
1+x
Identify odd function
1+x+x2
x+2
x-x3
x2 + x4
The Fourier constant bn for f(x)= x sinx in (-2,2) is
2
1
0
4
The trigonometric Fourier series of an even function does not have
Sine terms
Cosine terms
Constant term
harmonic terms
If f(x) = sinh(x) defined in -π<x<π then a0 and an values are
a0 = 0 , an = 1
a0 = 1 , an = 1
a0 = 0 , an = 0
a0 = 1 , an = 1
Which of the following functions cannot be expressed as a Fourier series ?
tanx
x
xsinx
cosx
nπ4
nπ8
nπ−8
0
The incorrect statement from the following choices is
The product of two even functions is an even function
The product of two odd functions is an even function
The product of an odd function and an even function is an even function
The product of an odd function and an even function is an odd function
The incorrect statement from the following choices is
sinx is an odd function
sin2x is an odd function
sinx2 is an odd function
sinx2 is an even function
What will be the value of
a0 in the Fourier Series of the above function in (−4, 4) ?1/4
4
-4
0
A half range series consists of
sine terms only
cosine terms only
both sine and cosine terms
either only sine terms or only cosine terms
sinx+cosx is
an odd function
an even function
neither an odd function nor an even function
both odd and even function
For any integer n the value of cosnπ is
1
0
-1
(-1)n
The Real part of eisx is
sinsx
i sinsx
cossx
cosx
f(x)=a2− x2 in the interval ∣x∣ ≤a , where a>0 means what and find the value of f(0) ?
f(x)= a2−x2 in the interval x ≤a and f(0) =1
f(x)= a2−x2 in the interval −a≤x ≤a and f(0) = a2
f(x)=a2− x2 in the interval 0≤x ≤1 and f(0) = a2
f(x)= a2−x2 in the interval −a≤x ≤a and f(0) = 0
f(x)= x2 in the interval ∣x∣ ≤1 means what and find the value of f(0) ?
f(x)= x2 in the interval x ≤1 and f(0) =1
f(x)= x2 in the interval −1≤x ≤1 and f(0) = 1
f(x)= x2 in the interval 0≤x ≤1 and f(0) = 0
f(x)= x2 in the interval −1≤x ≤1 and f(0) = 0
Infinite Fourier Transform pair is also called
complex form
Complex pair
complex transform pair
none of the above
a2+b2eax[acosbx−bsinbx]
a2+b2eax[acosbx+bsinbx]
a2+b2eax[bcosbx+asinbx]
none of the above
a2+s2eax[acossx−ssinsx]
a2+b2eax[acosbx+bsinbx]
a2+s2e−ax[acossx−ssinsx]
a2+s2e−ax[−acossx−ssinsx]
SinA sin B=
21[sin(A+B)+sin(A−B)]
21[sin(A+B)−sin(A−B)]
21[cos(A+B)+cos(A−B)]
21[cos(A−B)−cos(A+B)]
CosA sin B=
21[sin(A+B)+sin(A−B)]
21[sin(A+B)−sin(A−B)]
21[cos(A+B)+cos(A−B)]
21[cos(A−B)−cos(A+B)]
CosA Cos B=
21[sin(A+B)+sin(A−B)]
21[sin(A+B)−sin(A−B)]
21[cos(A+B)+cos(A−B)]
21[cos(A−B)−cos(A+B)]
SinA Cos B=
21[sin(A+B)+sin(A−B)]
21[sin(A+B)−sin(A−B)]
21[cos(A+B)+cos(A−B)]
21[cos(A−B)−cos(A+B)]
The inverse Fourier Transform of F[f(x)] is f(x) =
2π1∫−∞∞ F[s] dx = f(x)
2π1∫−∞∞F[s]eisx ds =f(x)
2π1∫−∞∞F[s] e−isxds =f(x)
2π1∫−∞∞F[s] cossx ds = f(x)
The complex form eisx and e−isx is
eisx = cossx + sinsx and e−isx = cossx − sinsx
eisx = cossx +isinsx and e−isx = cossx −isinsx
eisx = cossx and e−isx = sinsx
None of the above
The Imaginary part of eisx is
sinsx
i sinsx
cossx
cosx
The Fourier sine Transform of f(x) is Fs[f(x)]=
2π1∫−∞∞f(x) dx = Fs[s]
2π1∫0∞f(x) sinsx dx = Fs[s]
π2∫0∞f(x) sinsx dx = Fs[s]
2π1∫−∞∞f(x) cossx dx = Fs[s]
The inverse Fourier sine Transform of F−1{Fs[f(x)]} = f(x)
2π1∫−∞∞f(x) ds= Fs[s]
2π1∫0∞ Fs[s]sinsx ds=f(x)
π2∫0∞Fs[s]sinsx ds = f(x)
2π1∫−∞∞ Fs[s] cossx dx =f(x)
1. Find the nature of the one-dimensional wave equation.
Hyperbolic
Parabolic
Elliptic
None of These
The nature of the one-dimensional heat equation is
Circular
Elliptic
Parabolic
Hyperbolic
The nature of PDE 4uxx +3 uxy +3 uyy=0
Parabolic
Hyperbolic
Elliptic
Laplace
The PDE uxx + uyy = 0, is known as
1-D heat equation
1-D wave equation
Laplace equation
None of these
Let PDE uxx + uyy = ut, By method separation, we consider the solution
u(x,y)=X(x)Y(y)
u(x,y,t)=X(x)Y(y)T(t)
u(x,t)=X(x)T(t)
None of these
Let PDE c2(uxx + uyy )= ut, By is known as
2-D heat equation
2-D wave equation
Laplace equation
None of these
Let PDE c2(uxx + uyy )= utt, By is known as
2-D heat equation
2-D wave equation
Laplace equation
None of these
The nature of PDE 4uxx +3 uxy =0
Circular
Elliptic
Hyperbolic
Parabolic
The nature of PDE uxx +4 uxy +3 uyy,=0
Circular
Elliptic
Hyperbolic
Parabolic
A rod of length 10 m has temperature 300 C and 400 C at end points. What is the temperature gradient
10C per cm
30C per cm
20C per cm
None of these
In the steady state, 2-D heat equation reduces to
1-D heat equation
1-D wave equation
Laplace equation
None of these
In the steady state, the change in temperature at any point with respect to time is
00C
>00C
<00C
None of these
The ends A and B of a rod of length10cm are at 300C and 800C at end points until steady state prevails. Then Initial temperature distribution in the rod
10+(5x)/2
30+(5x)/2
30+5x
None of these
The ends A and B of a rod of length20cm are at 300C and 800C at end points until steady state prevails. Then the temperature of the rod at ends are changed to 400C and 600C respectively. Final temperature distribution (i.e. in Steady state) is
40+x
50+x
60+x
70+x
A partial differential equation requires
exactly one independent variable
two or more independent variables
more than one dependent variable
equal number of dependent and independent variables
Using substitution, which of the following equations are solutions to the partial differential equation?
The partial differential equation
is classified as
elliptic
parabolic
hyperbolic
none of the above
The partial differential equation
is classified as
elliptic
parabolic
hyperbolic
none of the above
The complete integral of z=px+qy+f(p,q)
z=px+qy
z=ax+by+f(a,b)
z=f(a,b)
none of the above
What is the order & degree of the p.d.e x2(∂x∂z)2=z(x−y∂y∂z)
1 & 2
2 & 1
2 & 2
none of the above
Singular solution of Partial differential equation can be obtained by
General solution
Complete solution
both a & b
none of the above
The condition of compatibility of partial differential equations f(x,y,z,p,q)=0 , g(x,y,z,p,q)=0 is
∂(p,q)∂(f,g)=0
∂(p,q)∂(f,g)=0
∂(g,q)∂(f,p)=0
∂(g,p)∂(f,q)=0
If u is homogeneous function of order n then ∂x∂u , ∂y∂u both are homogeneous function of order
n
n-1
n+1
n-2
If f(x,y)=0 then what is the value of dxdy is
fyfx
−fyfx
fxfy
−fxfy
An equation containing partial derivatives of one or more dependent variables of two or more independent variables
Ordinary Partial Differential Equation
Partial Differential Equation
Ordinary Differential Equation
Partially Ordinary Differential Equation
Find the Partial derivative of f with respect to y for f(x,y)=x+yy2
(x+y)22x+y
(x+y)22xy+y2
(x+y)2
(x+y)22x2+y2
Find ∂x∂f of f(x,y)=sin(1+yx)
cos(1+yx)
cos(1+yx)(1+y1)
−cos(1+yx)((1+y)2x)
sin(1+yx)(1+y1)
Find ∂x∂ffor f(x,y)=3e2x+7xy−3x
6e2x+7y−3
6e2x+7x−3
6ex+7y−3
6e2x+7y+7x−3
find ∂y∂f, given f(x,y)=ex+2xy2−4y at (0,3)
8
−4
−12
Find the partial derivative of fy for the function f(x,y)=(3x2+y2)3
3y(3x2+y2)2
3x2(3x2+y2)2
6(3x2+y2)2
6y(3x2+y2)2
Find ∂y∂f if f(x,y)=3cos(2y)−sin(x+y)
fy(x,y)=−6sin(2y)−cos(x+y)
fy(x,y)=−cos(x+y)
fy(x,y)=6sin(2y)+cos(x+y)
Find ∂x2∂2f if f(x,y)=x3+2x2y−3y+2x+5
3x2+4xy+2
6x+4
6x+4y
x2+3xy
if f(x,y)=x3−2xy+xy3+3y2 which of the following is true?
fx(x,y)=3x2−2y+y3 fy(x,y)=−2x+6y+3xy2 fxy(x,y)=6x
fx(x,y)=−2x+6y+3xy2 fy(x,y)=3x2−2y+y3 fxy(x,y)=−2+3y2
fxx(x,y)=6x fyy(x,y)=6+6xy
fxy(x,y)=−2+3y2
fxx(x,y)=6+6xy fyy(x,y)=6x
fxy(x,y)=−2+3y2
Find the first order partial derivative with respect to y
f(x,y)=x3y2+3xey
.
fy(x,y)=3x2y2+3ey
fy(x,y)=3x2y2+2x3y+3ey+3xey
fy(x,y)=2x3y+3xey
fy(x,y)=6x2+3ey
Find the Partial derivative of f with respect to y for
f(x,y)=x+yy2
(x+y)22x+y
(x+y)22xy+y2
(x+y)2
(x+y)22x2+y2
Given a contour plot of f(x,y) . What would be a good estimate of ∂x∂f at the origin?
0
1
1.5
2
Given a contour plot of f(x,y) . What would be a good estimate of ∂y∂f at the origin?
−32
-2
0
23
Find the gradient vector of f(x,y,z)=z2ln(xy)
<yz2,xz2,2z>
<xz2,yz2,2z>
<yz2, xz2,2zln(xy)>
<xz2,yz2,2zln(xy)>
f (x) = 2x - 5x6
If z is a function which depends on variables x and y, the change of z with respect to one of its variables is called as:
Total derivative.
Partial derivative.
Inexact differential.
I don't know :)
A partial differential equation has:
one independent variable.
equal number of dependent and independent variables.
more than one dependent variable.
two or more independent variables
If z is a function which depends on variables x and y, the change of z with respect to variable x can be expressed as
(∂x∂z)y
(∂x∂z)x
(∂z∂x)x
I don't know :)
If z = f (x, y) ; then its total differential can be expressed as
dz=(∂x∂z)ydx +(∂y∂z)xdy
dz=(∂x∂z)ydy +(∂y∂z)xdx
dz=(∂x∂z)y +(∂y∂z)x
dz=(∂x∂z)x +(∂y∂z)y
Find the second order partial derivatives of
f(x,y)=(3x+2y)4
fxx(x,y)=12(3x+2y)3, fyy(x,y)=24(3x+2y)2
fxx(x,y)=36(3x+2y)2, fyy(x,y)=8(3x+2y)3
fxx(x,y)=24(3x+2y)2, fxy(x,y)=32(3x+2y)
fxx(x,y)=108(3x+2y)2, fyy(x,y)=48(3x+2y)2
For an ideal gas, evaluate the product of partial derivatives:
(∂V∂P)T(∂P∂T)V(∂T∂V)P1
-1
R
None of them
The z-transform of a signal X(n) whose definition is given by X(z)=
n=0∑∞x(n)z−n is known asUnilateral Z-transform
Bilateral Z-transform
Rational Z-transform
None of the above
For what kind of signals one sided Z-transfrom is unique
All signals
Anti-causal signal
Causal signal
None of the above
Z-transform is linear
True
False
The Z-transform of
δ(n+k)>0 isz−k, z=0
zk,z=0
z−k, all z
zk,all z
Z-transform of the sequence {2k},k≥0 is z−2z
True
False
Z−transform of the sequence {k!ak},k≥0=eza
True
False
Z−transform of the sequence {ncr},(0≤r≤n) is (1+z)n
True
False
The value of the Radius of convergence of f(n)=2n,n<0 is
0< ∣z∣ <1
-2< ∣z∣
∣z∣ <2
z-plane
The ROC of u(n)=4n,for n<0;2n,for n≥0 is
0<z<1
z<4
2<z
2<z<4
If Z(un)=u(z), then n→∞limun=n→∞lim(z−1)u(z)
True
False
The Inverse Z−transform of(z+1)2zis
(−1)n+1
n(−1)n−1
(−1)n−1
n(−1)n+1
The value of sin nπ is
1
0
-1
n
The value of cos nπ= ------ and Cos 0=-------
0 and 0
(−1)n and 0
(−1)n and 1
1 and 1
The value of ∫cos5x dx =
5 sin5x
-5sin5x
5sin5x
−5sin5x
The value of ∫0π sin3x dx
32
−32
0
31
∫02π x sinx dx =
∣x(−cosx)−(−sinx)∣
∣x(cosx)−(sinx)∣
∣x(−cosx)−(−sinx)∣02π = 0
∣x(−cosx)−(−sinx)∣02π = −2π
∫02π x cosnx dx =
∣x(sinx)(−cosx)∣
∣∣∣∣x(nsinnx)−(−n2cosnx)∣∣∣∣
∣∣∣∣x(nsinnx)−(−n2cosnx)∣∣∣∣02π =0
∣∣∣∣x(nsinnx)−(−n2cosnx)∣∣∣∣02π =2
∫02π x cos(lnπ )x dx =
∣∣∣x(sin(lnπ )x)(−cos(lnπ )x)∣∣∣
∣∣∣∣∣x((lnπ )sin(lnπ )x)−(−(lnπ )2cos(lnπ )x)∣∣∣∣∣
∣∣∣∣∣x((lnπ )sin(lnπ )x)−(−(lnπ )2cos(lnπ )x)∣∣∣∣∣02π
= 0
∣∣∣∣x(nsinnx)−(−n2cosnx)∣∣∣∣02π
=2
The Fourier coefficient ao for f(x) = ex in (-π,π ) is
sinhπ/π
eπ+e-π
eπ-e-π
2sinhπ/π
The Fourier coefficient a0 for f(x) = x sinx in (-π,π) is
2π
2
π
-π
The Fourier constant bn for f(x)= x sinx in (-2,2) is
2
1
0
4
A Periodic function is given by a function which
has a period T= 2π
has a period T= π
satisfies f(t+T) = f(t)
satisfies f(t+T) = - f(t)
Find the sum of 1
1/2+1/3^2+1/5^2+……… using Fourier series expansion if f(x) = a when [0,π] and 2 π – x when [ π, 2 π].
π^2/8
π^2/4
π^2/16
π^2/2
A periodic function is defined as:
f(x+P) = f(x)
f(x) = -f(x)
f(x+nP) = f(x)
f(x) = f(-x)
The particular conditions that a function f(x) must fulfill in order that it may be expanded as a Fourier series is:
Gibbs phenomenon
Fourier–Mellin theorem
Dirichlet conditions
Convolution theorem
