Find  $L^{-1}\left(\frac{s}{s^2+25}\right)$  

Find  $L^{-1}\left(\frac{1}{s^2+1}\right)$  

 $L^{-1}\left(\frac{6}{\left(s\right)}-\frac{4s}{s^2+25}\right)$  What is the property use to find the Inverse Laplace Transform of this equation?

 $L^{-1\ }\left(\frac{4s}{s^2+25}+\frac{2}{3\left(s^2+1\right)}\right)$  

 $L\left(t^{\left(4\right)}\right)$  ?

 $L^{-1}\left(\frac{24}{s^5}\right)$ is  $t^4$  . What is  $L^{-1}\left(\frac{1}{s^{\left(5\right)}}\right)$  ?

 $L^{-1}\left(\frac{4}{s^{\left(3\right)}}\right)$  

 $L^{-1}\left(\frac{3}{s^2+36}\right)$  

 $L^{-1}\left(F\left(s-5\right)\right)=e^{5t}f\left(t\right)$  Based on first shifting property for Inverse Laplace transform, what is  $a$   value?

 $L^{-1}\left(\frac{1}{\left(s-3\right)^2}\right)$  

 $L^{-1}\left(\frac{s}{\left(s-4\right)^2+16}\right)$