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WorksheetsSK015 (1.3 : STOICHIOMETRY)
Total questions: 10
Worksheet time: 57mins
Consider the following reaction:
NH4NO3 + Na3PO4 --> (NH4)3PO4 + NaNO3
Which reactant is limiting, assuming we started with 30.0 grams of ammonium nitrate and 50.0 grams of sodium phosphate
(NH4)3PO4
NH4NO3
Na3PO4
NaNO3
Consider the following reaction:
NH4NO3 + Na3PO4 --> (NH4)3PO4 + NaNO3
Assuming we started with 30.0 grams of ammonium nitrate and 50.0 grams of sodium phosphate. What is the mass of NaNO3 that can be formed?
18.625 g
20.075 g
40.076 g
31.875 g
Write the balanced equation for the reaction given below:
CuCl2 + NaNO3 --> Cu(NO3)2 + NaCl
3CuCl2 + 2NaNO3 --> Cu(NO3)2 +2NaCl
CuCl2 + 2NaNO3 --> Cu(NO3)2 +2NaCl
CuCl2 + NaNO3 --> Cu(NO3)2 +2NaCl
2CuCl2 + 2NaNO3 --> Cu(NO3)2 +2NaCl
Balance the redox equation in acidic medium:
MnO4 - + S2O3 2- --> S4O6 2- + Mn 2+
30 H + + 2 MnO4 - + 10 S2O3 2- --> 2 Mn 2+ + 8 H2O + 5 S4O6 2-
16 H + + 2 MnO4 - + 5 S2O3 2- --> 2 Mn 2+ + 8 H2O + 5 S4O6 2-
16 H + + 2 MnO4 - + 10 S2O3 2- --> 2 Mn 2+ + 8 H2O + 5 S4O6 2-
Consider the following reaction:
CaCO3 + FePO4 --> Ca3(PO4)2 + Fe2(CO3)3
100 grams of calcium carbonate and 45.0 grams of iron (III) phosphate are reacted. What mass of the excess reactant(s) is left over?
55.225 g
56.225 g
85.225 g
59.225 g
Consider the reaction below:
CuCl2 + 2NaNO3 --> Cu(NO3)2 +2NaCl
If 15 grams of copper (II) chloride react with 20. grams of sodium nitrate, how much sodium chloride can be formed?
15.104 g
20.104 g
13.104 g
17.104 g
Choose the correct statement(s) of Limiting Reactant?
Reactant which is remained after the reaction completed.
Reactant which is completely used in reaction.
Determine the amount of product that will be formed.
The equation below shows the combustion reaction of ethene (C2H6) :
2C2H6 + 7O2 --> 4CO2 + 6H2O
If 16.4 L of C2H6 reacts with 0.980 mol of O2 how many liters of carbon dioxide gas will be produced?
15.544 L
12.544 L
10.544 L
Balance the redox equation in basic medium:
ClO2 --> ClO2 - + ClO3 -
6 OH - + 2 ClO2 --> ClO2 - + ClO3 - + 3H2O
2 OH - + 2 ClO2 --> ClO2 - + ClO3 - + H2O
10 OH - + 2 ClO2 --> ClO2 - + ClO3 - + 5H2O
CaCO3 + FePO4 --> Ca3(PO4)2 + Fe2(CO3)3
After the above reaction is completed, 20.0 g of FePO4 is left over. Which compound is the limiting reactant?
FePO4
Fe2(CO3)3
CaCO3
Ca3(PO4)2
