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Worksheets

Sucesiones aritméticas

Total questions: 6

Worksheet time: 4mins

Name
Class
Date
1.

Escoja la formula explicita expresada correctamente

a)

 d(n)=n+b(n1)d\left(n\right)=n+b\left(n-1\right)  

b)

 a(n)=a(n1)+ba\left(n\right)=a\left(n-1\right)+b  

c)

 d(n)=n +b(n1)d\left(n\right)=n\ +b\left(n-1\right)  

d)

 a(n)=a(1)+b(n1)a\left(n\right)=a\left(1\right)+b\left(n-1\right)  

2.

Escoja la formula recursiva expresada correctamente

a)

 {a(1)=n  }  {a(n)=a(n1)+b}\left\{a\left(1\right)=n\ \ \right\}\ \ \left\{a\left(n\right)=a\left(n-1\right)+b\right\}  

b)

 {a(1)=n  }  {a(n)=a(1)+b}\left\{a\left(1\right)=n\ \ \right\}\ \ \left\{a\left(n\right)=a\left(1\right)+b\right\}  

c)

 {a(n)=1  }  {a(n)=a(n1)+b}\left\{a\left(n\right)=1\ \ \right\}\ \ \left\{a\left(n\right)=a\left(n-1\right)+b\right\}  

d)

 {a(n)=a(1)}  {b(n1)}\left\{a\left(n\right)=a\left(1\right)\right\}\ \ \left\{b\left(n-1\right)\right\}  

3.

Encuentra la formula explicita para la sucesión aritmética: -13, -5, 3, 11, 19,...

a)

d(n)=13+8(n1)d\left(n\right)=-13+8\left(n-1\right)

b)

d(n)=138(n1)d\left(n\right)=-13-8\left(n-1\right)

c)

d(n)=8+13(n1)d\left(n\right)=-8+13\left(n-1\right)

d)

d(n)=813(n1)d\left(n\right)=8-13\left(n-1\right)

4.

Encuentra la formula recursiva para la sucesión aritmética: 9, 14, 19, 24,...

a)

{a(1)=9} {a(n)=a(n1)+5} \left\{a\left(1\right)=9\right\}\ \ \left\{a\left(n\right)=a\left(n-1\right)+5\right\}\

b)

{a(1)=9} {a(n)=a(n1)5}\left\{a\left(1\right)=9\right\}\ \ \left\{a\left(n\right)=a\left(n-1\right)-5\right\}

c)

{a(1)=5} {a(n)=a(n1)+9}\left\{a\left(1\right)=5\right\}\ \ \left\{a\left(n\right)=a\left(n-1\right)+9\right\}

d)

{a(1)=5} {a(n)=a(n1)9}\left\{a\left(1\right)=5\right\}\ \ \left\{a\left(n\right)=a\left(n-1\right)-9\right\}

5.

Encuentra el quinto término para la siguiente formula:

 c(n)=6+5(n1)c\left(n\right)=-6+5\left(n-1\right)  

a)

 c(5)=14c\left(5\right)=14  

b)

 c(5)=14c\left(5\right)=-14  

c)

 c(5)=30c\left(5\right)=-30  

d)

 c(5)=30c\left(5\right)=30  

6.

Encuentra el segundo término para la siguiente formula:

 {c(1)=7}  {c(n)=c(n1)+12} \left\{c\left(1\right)=-7\right\}\ \ \left\{c\left(n\right)=c\left(n-1\right)+12\right\}\   

a)

 c(2)=5c\left(2\right)=5  

b)

 c(2)=5c\left(2\right)=-5  

c)

 c(2)=17c\left(2\right)=-17  

d)

 c(2)=17c\left(2\right)=17