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WorksheetsApplication of Derivatives 12th
Total questions: 25
Worksheet time: 1hrs 15mins
What is the increasing interval for the function below?
(−∞,∞)
(−∞,2]
(−∞,6]
(−6,6)
What is the decreasing interval(s) on the function shown?
(−7, −6) and (−2, 4)
(−7, 0) and (−2, 4)
(−7, −6) and (−2, 0)
(−7, 0) and (4, 5)
The intervals in which the function f given by f (x) = x2 – 4x + 6 is increasing is
(−∞, 2)
(2, ∞)
(−∞, ∞)
none of these
The logarithmic function is increasing on
(0, 1)
(0, ∞)
(1, ∞)
(−∞, ∞)
The interval in which y=x2e–x is increasing is
(−2, 0)
(−∞, ∞)
(2, ∞)
(0, 2)
The interval on which the function f (x) = 2x3 + 9x2 + 12x – 1 is decreasing is:
[−1, ∞)
[−2, −1]
(−∞, −2]
[−1, 1]
Which of the following functions is decreasing on (0, 2π)
sin2x
tanx
cosx
cos3x
The interval in which y=x2e–x is increasing is
(−2, 0)
(−∞, ∞)
(2, ∞)
(0, 2)
y = x (x – 3)2 decreases for the values of x given by :
1<x<3
x<0
x>0
0<x<23
If dydx=∞ , then the tangent at a point P(x,y) on the curve is perpendicular to the x- axis.
False
True
For Maximum point : (i) dydx=0 ; (ii) dx2d2y < 0
False
True
The smallest value of the polynomial
x3−18x2+96x in [0, 9] is126
0
135
160
The maximum value of
sinx.cosx is1/4
1/2
2
22
The absolute maximum and the absolute minimum values of the function f(x)=4x−2x2 in [-2, 4.5] is
8, -10
4, - 2
0, 3
3, 6
The points at which the function changes its nature from increasing to decreasing or from decreasing to increasing are called
(a)
The slope of the normal to the curve x=acos3θ, y=asin3θ at θ=4π is
(a)
The equation of the tangent line to the curve y = x2 – 2x +7 which is parallel to the line 2x – y + 9 = 0 is
y – 2x – 3=0
y +2x – 3=0
y – 2x + 3=0
y +2x + 3=0
The equation of normal to the curve y = tan x at (0, 0) is ________
x−y=0
x+y=1
x+y=0
x−y=1
The equation of the normal to the curve y=x4– 6x3+13x2 – 10x+5 at (0, 5) is
x +10y+50=0
x – 10y+50=0
x – 10y−50=0
x +10y+50=0
The equations of all lines having slope 0 which are tangent to the curve y=x2−2x+31 is
y=1
2y=1
2y+1=0
y+1=0
Determine the point on the curve f(x)=(2x-1)2 where the tangent is parallel to the line y=4x-2
(0 , 1)
(1 , 9)
(1/2 , 0)
(1 , 1)
What is the equation of the normal line to the curve y=3x2+2x at x=1 ?
y=8x−3
y=8x−13
y=−81x+841
y=81x+839
The point on the curve y2=xat which the tangent is parallel to the line joining (1,4) and (3,2) is
(5,6)
(1/2,-1/2)
(1/2,3/2)
(-1/2,1/2)
What is the equation of the line tangent to the curve y = x2 at x = 1?
y = 2x + 1
y = 2x - 1
y = -2x + 1
y = x - 1
Find the equation of the normal line at x = 0 of:
f(x) = x3+ex
y=−x+1
y= x+1
y=−x −1
y=x − 1
