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Worksheets

Genetics & Biotechnology

Total questions: 25

Worksheet time: 25mins

Name
Class
Date
1.

Position of a gene on chromosome is called

a)

Locus

b)

Factor

c)

Cistron

d)

Nucleosome

2.

In a monohybrid cross, the ratio of F2 true breeding dominant and true breeding recessive would be

a)

50:50

b)

25:25

c)

75:25

d)

25:75

3.

In a dihybrid cross, F2 phenotypic ratio is 13:3.It is a case of

a)

Complementary genes

b)

Epistatic genes

c)

Multigenic inheritance

d)

Incomplete dominance

4.

A cross between parent and hybrid is known as

a)

Test cross

b)

Back cross

c)

Monohybrid cross

d)

Reciprocal cross

5.

The law of segregation of gametes is also known as the law of purity of gametes because

a)

Gametes have only one of the two alleles for each character

b)

Gametes cannot be contaminated

c)

Gametes are very different types of cells

d)

It was just another name adopted accidentally

6.

A haploid set of all the genes present in a gamete is called

a)

Genotype

b)

Phenotype

c)

Genome

d)

Linkage group

7.

In Mirabilis jalapa when two pink flowered plants were crossed with each other, the F2 generation produced 40 red, 80 pink and 40 white flowering plants. This is a case of

a)

Duplicate genes

b)

Lethal genes

c)

Incomplete Dominance

d)

Epistasis

8.

The factors which represent the contrasting pairs of characters are called

a)

Dominant and recessive

b)

Alleles

c)

Homologous pairs

d)

Determinants

9.

Mendel observed red flowers in F1 when he crossed red and white because of

a)

Dominance

b)

Recessive gene

c)

Law of Independent Assortment

d)

Law of Segragation

10.

How would you test whether a Pea plant is pure or hybrid for tallness?

a)

Cross it with another tall Pea plant of unknown genotype

b)

Cross it with a homozygous dwarf pea

c)

Cross it with a pure tall pea plant

d)

Cross it with any pea plant

11.

A modified dihybrid mendelian ratio of 9:3:4 indicates

a)

Supplementary genes

b)

Complementary genes

c)

Lethal genes

d)

Epistatic genes

12.

ABO blood grouping shows

a)

Polygenes

b)

Dominant-recessive genes

c)

Codominant genes

d)

Both codominant and dominant recessive genes

13.

Allele is

a)

Segment of gene

b)

Form of a gene

c)

Special kind of gene

d)

A muton

14.

An individual having similar unit factors of a character is

a)

Heterozygote

b)

Homozygote

c)

Dominant

d)

Recessive

15.

Checkerboard method of calculations was developed by

a)

Mendel

b)

Bateson

c)

Punnet

d)

Morgan

16.

Some gene loci on two homologous chromosomes produce different phenotypes. They bear

a)

Homozygous alleles

b)

Heterozygous alleles

c)

Two different genes

d)

Pleiotropic genes

17.

Repeated selfing produces

a)

Heterozygosity

b)

Homozygosity

c)

Homozygosity in some and heterozygosity in other traits

d)

Pure hybrids

18.

A phenotypic ratio not obtained by Mendel was

a)

3:1

b)

1:2:1

c)

1:1:1:1

d)

9:3:3:1

19.

First generation after a cross is

a)

First Filial generation

b)

F1 generation

c)

Second filial generation

d)

Both A and B

20.

The number of genotypes produced by gametes Y and y would be

a)

1

b)

12

c)

3

d)

4

21.

A single heterozygous yellow wrinkled seeded Pea plant shall produce gametes

a)

YR only

b)

yr only

c)

Yr and yr

d)

YR and yR

22.

Genetics deals with

a)

Heredity and variations

b)

Heredity

c)

Mutations

d)

Nuclear and cytoplasmic inheritance

23.

Epistatic gene differs from dominant gene in

a)

Epistatic and hypostatic genes are present at different loci

b)

Epistatic gene is non allelic

c)

Epistatic gene never expresses itself independently

d)

All of the above

24.

A pea with white flowers was crossed to another pea with white flowers. When selfed the F2 generation produced purple and white in the ratio 9:7. The reason for the results is that

a)

It is a typical monohybrid Mendelian ratio

b)

Purple flower colour is dominant over the white

c)

It is a complementary factor

d)

None of the above

25.

When a yellow mouse was crossed to another yellow mouse, the F1 generation produces yellow and brown-black mice in the ratio 2:1. The yellow mice are never homozygous. The reason is

a)

Homozygous yellow cannot survive due to lethal effect of genes

b)

Yellow mice are not very suitable to live

c)

There is no formation of zygotes with homozygous yellow constitution

d)

None of the above