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Studying cells

Total questions: 20

Worksheet time: 22mins

Name
Class
Date
1.
When observing a specimen through a light microscope, an observer uses _______________ to distinguish individual components of cells.
a)
a beam of electrons
b)
radioactive isotopes
c)
special stains
d)
high temperatures
2.
This microscope is good for observing living specimens.
a)
electron microscope
b)
light microscope
c)
radioscope
3.
This microscope is good for looking closely at the smaller organelles.
a)
electron microscope
b)
light microscope
c)
radioscope
4.
Which electron microscope delivers a high level of surface detail?
a)
Scanning Electron Microscope (SEM)
b)
Transmission Electron Microscope (TEM)
c)
Light Microscope
5.
Which electron microscope provides details of a cell's internal structures?
a)
Scanning Electron Microscope (SEM)
b)
Transmission Electron Microscope (TEM)
c)
Light Microscope
6.

The ________ of the microscope would give you the SMALLEST field of view.

a)

low power objective

b)

medium power objective

c)

high power objective

d)

stage

7.
Find total magnification for:
Eyepiece = 10X 
Objective lens = 4X
 
a)
4x
b)
6x
c)
14x
d)
40x
8.
Which part of the microscope is this?
a)
fine focus
b)
stage
c)
occular lens
d)
objective lens
9.

What is needed to produce an image for a transmission electron microscope?

a)

Light

b)

A living cell

c)

A vacuum

d)

A very thin specimen

10.

Calculate the actual size of a mesophyl cell if the its drawing has a length of 350mm and the magnification of the drawing is 700x

a)

0.002μm

b)

0.02nm

c)

0.002nm

d)

0.0002μm

11.

If the nucleus is 650 times bigger than a particular mitochondria, what is the size of this mitochondria (in nm) if the nucleus measures 130Um in diameter

(a)  

12.

The intermembrane space of a mitochondrion measures 1.25nm in width. What is the magnification of the diagram of that intermembrane space if it measures 0.75mm in width.

a)

600x

b)

6000x

c)

60x

d)

60,000x

13.
Which of the following explains why mitochondria structure and function cannot be studied using a light microscope
a)
Mitochondria is enclosed by a double membrane
b)
Mitochondria size is too small for its internal structures to be magnified by the light microscope
c)
Mitochondria size is too small to for its internal structures to the resolved by a light microscope
d)
Mitochondria must be alive for it to be studied
14.

the average lysosome has a size of 1.2µm and the average ribosome has a size of 25nm. How many ribosomes can be packed into a lysosome?

(a)  

15.

The magnification of a diagram of a leaf is 210x. And the actual thickness of the leaf is 243µm. What is the thickness of the drawing in cm?

(a)  

16.

When would you use the diaphragm?

a)

When you wanted to move the stage

b)

When you wanted to adjust the light

c)

When you wanted to put the microscope away

d)

When you want to change the objective lens

17.

A primary objective of cell fractionation is to

a)

view the structure of cell membranes.

b)

determine the size of various organelles

c)

separate the major organelles so that their particular functions can be determined

d)

identify the enzymes outside the organelle

18.

In the fractionation of homogenized cells using centrifugation, the primary factor that determines whether a specific cellular component ends up in the supernatant or the sediment is?

a)

the relative solubility of the component.

b)

the size and weight of the component

c)

the percentage of carbohydrates in the component

d)

the number of enzymes in the fraction

19.

Which of the following correctly lists the order in which cellular components will be found in the sediment when homogenized cells are treated with increasingly rapid spins in a centrifuge?

a)

ribosomes, nucleus, mitochondria

b)

chloroplasts, ribosomes, vacuoles

c)

nucleus, ribosomes, chloroplasts

d)

nucleus, mitochondria, ribosomes

20.

In homogenisation, a cold buffering solution is used. What is the purpose of this buffering solution?

(a)